Answer:
The pressure is changing at 
Step-by-step explanation:
Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.
We know that the volume is decreasing at the rate of
and we want to find at what rate is the pressure changing.
The equation that model this situation is

Differentiate both sides with respect to time t.

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

Apply this rule to our expression we get

Solve for 

when P = 23 kg/cm2, V = 35 cm3, and
this becomes

The pressure is changing at
.
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Answer:
The enrollment after 5 years is 10,724
Step-by-step explanation:
Generally, we can have the depreciation formula written as follows;
A = P(1 - r)^t
A is the number of enrollment in after a certain number of years t
P is the initial population which is 13,500
r is the rate of depreciation which is 4.5% = 4.5/100 = 0.045
t = 5 years
Substituting these values, we have it that;
A = 13,500(1-0.045)^5
A = 10,723.84
We have a ratio of 3 hours / 7.5 miles
We want to know how many miles he can walk in 1 hour so, divide both sides by 3 -> 1 hour / 2.5 miles
He is walking at 2.5 mph
Answer:
I would say that the answer is A. -4x + 9y = 11
Hope it helps, sry if it's wrong. It shouldn't be though.