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nikklg [1K]
3 years ago
10

There are 16 types of flowers used to decorate for a party. Twelve of the flowers types last an average of 4 days before they wi

lt. The remaining flowers last an average of 6 days.
What is the average number of days before the flowers wilt?

Enter your answer in the box.
Mathematics
1 answer:
Sergio [31]3 years ago
8 0
16 - 12 = 4 flowers
4f = 6 days
1 flower = 1.5 days
1.5 × 16 = 24 days
Have a good day!
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A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per
Tems11 [23]

Answer:

The pressure is changing at \frac{dP}{dt}=3.68

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of \frac{dV}{dt}=-4 \:{\frac{cm^3}{min}} and we want to find at what rate is the pressure changing.

The equation that model this situation is

PV^{1.4}=k

Differentiate both sides with respect to time t.

\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)

Apply this rule to our expression we get

V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0

Solve for \frac{dP}{dt}

V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}

when P = 23 kg/cm2, V = 35 cm3, and \frac{dV}{dt}=-4 \:{\frac{cm^3}{min}} this becomes

\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68

The pressure is changing at \frac{dP}{dt}=3.68.

7 0
4 years ago
Read the following statement.
nekit [7.7K]
Bro... ahahaha the answer is D DDDDDDDDDDDDDDD peace man 

8 0
3 years ago
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Plsss help me !!!!
Yuri [45]

Answer:

The enrollment after 5 years is 10,724

Step-by-step explanation:

Generally, we can have the depreciation formula written as follows;

A = P(1 - r)^t

A is the number of enrollment in after a certain number of years t

P is the initial population which is 13,500

r is the rate of depreciation which is 4.5% = 4.5/100 = 0.045

t = 5 years

Substituting these values, we have it that;

A = 13,500(1-0.045)^5

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4 0
3 years ago
Miguel is going for a walk. he takes 3 hours to walk 7.5 miles. what is his speed?
daser333 [38]
We have a ratio of 3 hours / 7.5 miles
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Write a linear equation in standard form for the line that goes through (-14,-5) and (4,3)
olganol [36]

Answer:

I would say that the answer is A. -4x + 9y = 11

Hope it helps, sry if it's wrong. It shouldn't be though.

8 0
3 years ago
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