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Grace [21]
3 years ago
13

Solve for x. 3x - 13 = 2 (SHOW YOUR WORK)

Mathematics
1 answer:
Eddi Din [679]3 years ago
7 0

3x-13=2

move -13 to the other side

sign changes from -13 to +13

3x-13+13=2+13

3x=2+13

3x=15

divide both sides by 3 to get x by itself

3x/3=15/3

cross out 3 and 3, divide by 3 and then becomes 1*1*x=x

x=15/3

x=5

answer:

x=5

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Which is equation in point slope form for the given point and slope. Point5,9 slope2
Sedbober [7]

Answer: y - 9 = 2(x - 5)

Step-by-step explanation:

Point slope form: y - y1 = m(x - x1)

substitute 5 for x1 and 9 for y1 and 2 for m

x1 = 5

y1 = 9

m = 2

you get y - 9 = 2(x - 5)

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Line m has no y
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If the line does not have a y int, then it means it does not cross the y axis....that means it is a vertical line.....its x int is (3,0)...so this equation for the line is x = 3

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the sum of 2 numbers is 49. Twice the smaller number is 97 less than 3 times the larger number. What are the numbers?
ivanzaharov [21]

Answer:

let the larger and  smaller number be x and y respectively

first condition

x + y = 49

second condition

3x = 2y+97

3x-2y =97

Multiplying first condition by two and adding both equations

2x + 2y = 98

<u>3x -2y = 97</u>

5x =  195

x = 195/5 = 39

putting the value of x in

x + y = 49

y = 49 -39 = 10

again

Step-by-step explanation:

3 0
2 years ago
Pls help asap important assessment.
Alex73 [517]
I think The answer is A
5 0
2 years ago
Find the solution set of this inequality|10x+20| ≤10
Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

|10x+20|\leq 10

Firstly, we will find critical values

so, let's assume it is equal

|10x+20|= 10

now, we can break absolute sign

For |10x+20|= -(10x+20):

-(10x+20)= 10

we can solve for x

-10x-20= 10

Add both sides by 20

-10x-20+20= 10+20

-10x= 30

Divide both sides by -10

and we get

x=-3

For |10x+20|= (10x+20):

(10x+20)= 10

we can solve for x

10x+20= 10

Subtract both sides by 20

10x+20-20= 10-20

10x= -10

Divide both sides by 10

and we get

x=-1

so, critical values are

x=-3

x=-1

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For (-\infty,-3):

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

|10\times -5+20|\leq 10

|-50+20|\leq 10

30\leq 10

so, this is FALSE

For [-3,-1]:

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

|10\times -2+20|\leq 10

|-20+20|\leq 10

0\leq 10

so, this is TRUE

For (-1,\infty):

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

|10\times 0+20|\leq 10

|0+20|\leq 10

20\leq 10

so, this is FALSE

so, solution is

[-3,-1]

7 0
3 years ago
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