find two consecutive integers such that twice the first added to three times the second is equal to 83
2 answers:
Let the first number=x and the second number =x+1 so 2(x)+3(x+1)=83 2(16)+3(17)=83 2x+3x+3=83 32+51=83 5x=83-3 5x=80 5x/5=80/5 x=16 16+1=17 Therefor the two consecutive integers are 16 and 17
First number- a
second number- a + 2
a + a + 2 = 83
2a = 81
40.5 =
41
first number - 41
second number - 43
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