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mr_godi [17]
3 years ago
15

Please help! will mark brainliest

Mathematics
2 answers:
nasty-shy [4]3 years ago
7 0

Answer:

The first one is true and the second one is false I think

Margaret [11]3 years ago
6 0

Answer:

Statement Number One- True

Statement Number Two- False

Step-by-step explanation:

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3 years ago
Which expression is equivalent to \root(3)(x^(5)y)
san4es73 [151]

Answer:

\sqrt[3]{x^{5}y} = x^{\frac{5}{3}}y^\frac{1}{3}

Step-by-step explanation:

Given

\sqrt[3]{x^{5}y}

Required

The equivalent expression

We have:

\sqrt[3]{x^{5}y}

Rewrite as an exponent

\sqrt[3]{x^{5}y} = (x^{5}y)^\frac{1}{3}

Open bracket

\sqrt[3]{x^{5}y} = x^{5*\frac{1}{3}}y^\frac{1}{3}

\sqrt[3]{x^{5}y} = x^{\frac{5}{3}}y^\frac{1}{3}

6 0
3 years ago
Solve for 2cos^2theta + 13costheta = -6. theta is >= 0 and < 360 degrees
LiRa [457]
\\ 2cos^2 \theta+13cos \theta=-6 \\ 2cos^2 \theta+13cos \theta+6=0 \\ 2cos^2 \theta+12cos \theta+1cos \theta+6=0 \\ 2cos \theta(cos \theta+6)+1(cos \theta+6)=0  \\ (2cos\theta +1)(cos\theta+6)=0 \\

cos\theta+6=0 \\ cos\theta=-6 \\    \\ cos(x)=|a| \leq 1 \\ |-6| \geq 1 \\  \\


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7 0
3 years ago
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