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Leya [2.2K]
3 years ago
14

For what values of k does kx^(2)-3x+2=0 have two equal real roots?

Mathematics
2 answers:
ANTONII [103]3 years ago
8 0

Answer:


Step-by-step explanation:

Therefore discriminant = b^2-4ac =0

b=-k, a=3,c=2


b^2-4ac= (-k)^2-4*3*2=0

k^2-24=0

k^2=24

k= +/- 2sqrt(6)


yaroslaw [1]3 years ago
5 0

Tienes que usar la fórmula cuadrática:


(-b +/- √(b^2-4ac))/2a

Primero identificas los valores de a,b y c en kx^2-3x+2=0


K=a, b=-3, c=2


Luego sustituis en la fórmula y te queda:


(3+/-√(9-8k))/2k


Para que las raíces Sena reales se tienen que cumplir que 9-8k>=0




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