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Law Incorporation [45]
4 years ago
14

Standard form.......

Mathematics
1 answer:
alex41 [277]4 years ago
3 0
Hi!

The correct answer is 14.71 or 14 71/100 

To get this you need to look closely at the text the word fourteen is in standard form 14 and seventy-one hundredths in standard form is 0.71 or 71/100 put them together and the answer is 14.71 or 14 71/100 
You might be interested in
What’s the answer please
skad [1K]

Answer:

h  ≤ 124 / 9

or

h  ≤ 13.78

Step-by-step explanation:

(3/4) (12h - 32) ≤ 100      (multiply both sides by 4)

(3) (12h - 32) ≤ 100 (4)

(3) (12h - 32) ≤ 400   (distribute 3 into the parenthesis)

(12h)(3) - (32)(3) ≤ 400   (expand left side terms)

36h - 96 ≤ 400   (add 96 to both sides)

36h  ≤ 400  + 96

36h  ≤ 496  (divide both sides by 36)

h  ≤ 496 / 36   (sinmplify)

h  ≤ 124 / 9

or

h  ≤ 13.78

3 0
3 years ago
The surface of a pond is being covered by oil leaking from a pipeline. The amount of surface area covered by the oil is doubling
fomenos

Answer:

Count

Step-by-step explanation:

Suppose that each day double 2, second day , will double 4, and for third day it's 16, etc.

For like those questions, just count.

Those questions are very simple, but other questions not like those, is not too simple.

7 0
2 years ago
Which number is the greater?<br><br> -3/12 or -1
MA_775_DIABLO [31]

Answer:

-3/12

Step-by-step explanation:

In negative numbers, it's basically the opposite of regular numbers.

Let's explain negative numbers as debts. Let's say you owe a friend 1 dollar, and another 2 dollars. In a sense, you'll have -1 dollars, and -2 dollars. Which one is the greater number? It'll be -1 as you're only losing 1 dollar. Same goes here. Although 1 is a greater number than 3/12, in negative form it isn't.

7 0
3 years ago
The volume V of a rectangular prism with length l, width w, and height h is v equals l times w times h. What is the width of a r
Iteru [2.4K]

Answer:

The answer is 3 inch

Step-by-step explanation:

To start off, the equation you want to use the formula V=whl

Next, you simply plug in the values you already know, so you have 450=w*20*7.5

After you do that you multiply 20 times 7.5 to get which is 150, which leaves you with 450= w *150 to solve for w, you need to isolate it. To do that you divide 450 by 150. You are left with the answer of 3.

6 0
4 years ago
Read 2 more answers
Larry and Paul start out running at a rate of 5 mph. Paul speeds up his pace after 5 miles to 10 mph but Larry continues the sam
klasskru [66]
<h2>Hello!</h2>

The answer is:

They will be 10 miles apart after 3 hours.

<h2>Why?</h2>

To calculate how long after they start will they be 10 miles apart, we need to assume that after 1 one hour, they were at the same distance (5 miles), then, calculate the time when they are 10 miles apart, knowing that Paul increased its speed two times, running first at 5mph and then, at 10 mph.

The time that will pass to be 10 miles apart can be calculated using the following equation:

TotalTime=TimeToReach5miles+TimeToBe10milesApart

Calculating the time to reach 5 miles for both Larry and Paul, at a speed of 5 mph, we have:

x=xo+v*t\\\\5miles=0+5mph*t\\\\t=\frac{5miles}{5mph}=1hour

We have that to reach a distance of 5 miles, they needed 1 hour. We need to remember that at this time, they were at the same distance.

If we want to know how many time will it take for them to be 10 miles apart with Paul increasing its speed to 10mph, we need to assume that after that time, the distance reached by Paul will be the distance reached by Larry plus 10 miles.

So, for the second moment (Paul increasing his speed) we have:

For Larry:

x_{L}=5miles+5mph*t

Therefore, the distance of Paul will be equal to the distance of Larry plus 10 miles.

For Paul:

x{L}+10miles=xo+10mph*t\\\\5miles+5mph*t+10miles=5miles+10mph*t\\\\5miles+10miles-5miles=10mph*t-5mph*t\\\\10miles=5mph*t\\\\t=\frac{10miles}{5mph}=2hours

Then, there will take 2 hours to Paul to be 10 miles apart from Larry after both were at 5 miles and Paul increased his speed to 10 mph.

Hence, calculating the total time, we have:

TotalTime=TimeToReach5miles+TimeToBe10milesApart

TotalTime=1hour+2hours=3hours

Have a nice day!

3 0
4 years ago
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