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2 years ago

Reduce 7y + 2y 2 - 7 by 3 - 4y?

Mathematics

2 answers:

Hatshy [7]2 years ago

6 0

Answer:

the correct answer is

2 y2 + 11 y - 10

Pepsi [2]2 years ago

3 0

(7y+2y2−7)−(3−4y)

=7y+4y+2y2−7−3

=11y−2y2−10

Hope this helps

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Find the value of x. Round to the nearest tenth.

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Step-by-step explanation:

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timama [110]

Answer:

(a)The missing measurements are 9 feet and $16\frac{1}{4}$ feet$ .

(b)Therefore, the length of the fence is $97\frac{1}{2}$ feet$

Step-by-step explanation:

The diagram of the yard is attached below.

(a)I have labeled the missing dimensions of the yard as x and y.

Therefore:

$y+8\frac{1}{4}=17 \frac{1}{4}\\y=17 \frac{1}{4}-8\frac{1}{4}\\y=9$ feet$

Similarly:

$x+15\frac{1}{4}=31\frac{1}{2}\\x=31\frac{1}{2}-15\frac{1}{4}\\x=31-15+\frac{1}{2}-\frac{1}{4}\\x=16+\frac{1}{4}\\x=16\frac{1}{4}$ feet$

The missing measurements are 9 feet and $16\frac{1}{4}$ feet$ .

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Length = $31\frac{1}{2}$ feet$

Width = $17 \frac{1}{4}$ feet$

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Therefore, the length of the fence

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2 years ago

Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [

Darya [45]

Answer:

A=3 and B=6

Step-by-step explanation:

Increasing and Decreasing Intervals of Functions

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

$f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9$

Computing the first derivative:

$f' ( x ) = - 6 x^3 + 54 x - 108$

We find the critical points equating f'(x) to zero

$- 6 x^3 + 54 x - 108=0$

Simplifying by -6

$x^2 -9 x +18=0$

We get the critical points

$x=3,\ x=6$

They define the following intervals

$(-\infty,3),\ (3,6),\ (6,+\infty)$

Thus A=3 and B=6

3 0

2 years ago