Simplify the expression:

Toby just graduated from four years of college. at the beginning of each year, he took out a stafford loan with a principal of $

Mila [183]

If he starts paying after four years, the worth of the loans by then is b. $31,616.16

This refers to the amount collected from a lender to be repaid after a given time, usually with added interest.

Hence, we can see that:

The effective monthly interest rate is:

i = 0.053/12 = 0.0044

The effective annual interest rate is:

i = (1 + 0.0044)^12 -1 = 0.0543

The present worth of all the loans is:

P = 6125 + 6125 (1 + 0.0543)^-1 + 6125 (1 + 0.0543)^-2 + 6125(1 + 0.0543)^-3

P = $22,671.40

If he pays them prompty, then the total lifetime cost would be

P = 22671.40 (1 + 0.0543)^4 = $31,616.16

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6 0

2 years ago

the animal shelter has space for 800 animals there were already 468 animals at the shelter after a storm a hundred ninety two mo

Anna007 [38]

Answer:

It is reasonable.

Step-by-step explanation:

If you add 468 (amount of animals already there) and add how ever many more coming (192) then you'll get 680. If you add 100 more that will only be 780 animals.

6 0

3 years ago

Calculus= Integrate 5^x dx please break down how answer is 1/6x^6+C

aleksley [76]

Answer:

$\int\limits {5^x} \, dx = \frac{5^x}{ln\ x} + c$

Step-by-step explanation:

Note that the integral of $5^x$ is not $\frac{1}{6}x^6 + c$

The solution is as follows:

Given

$5^x$

Required

Integrate

Represent the given expression using integral notation

$\int\limits {5^x} \, dx$

This question can't be solved directly;

We'll make use of exponential rules which states;

$\int\limits {a^x} \, dx = \frac{a^x}{ln\ x} + c$

By comparing $\int\limits {5^x} \, dx$ with $\int\limits {a^x} \, dx$ ;

we can substitute 5 for a;

Hence, the expression $\int\limits {a^x} \, dx = \frac{a^x}{ln\ x} + c$ becomes

$\int\limits {5^x} \, dx = \frac{5^x}{ln\ x} + c$

-------------------------------------------------------------------------------------

However, the integral of $x^5$ is $\frac{1}{6}x^6 + c$

This is shown below:

Given that $x^5$

Applying power rule;

Power rule states that

$\int\limits{x^n}\ dx = \frac{x^{n+1}}{n+1} + c$

In this case ( $x^5$ ), n = 5;

So, $\int\limits{x^n}\ dx= \frac{x^{n+1}}{n+1} + c$

becomes

$\int\limits{x^5}\ dx = \frac{x^{5+1}}{5+1} + c$

$\int\limits{x^5}\ dx = \frac{x^{6}}{6} + c$

$\int\limits{x^5}\ dx= \frac{x^{6}}{6} + c$

4 0

3 years ago

Phil received a prize of x dollars from a poker tournament. The tournament cost him 100 dollars to enter. What were Phil's net w

ValentinkaMS [17]

Phil gets x dollars, but before he gets x dollars, he needs to pay 100 dollars to enter the tournament. Therefore the net winning is not x dollars but you should substract 100 dollars from x.
So, the expression of the net winning will be x-100

8 0

3 years ago

Read 2 more answers

Identify the vertex of the function graphed below.

mash [69]

Where is the graph at ????

8 0

3 years ago