I´d say "d" is the distance from the eye to the wall.
Now substracting 1.2-1 you´ll get the distance of the wall of the smallest triangle = 0.2 And you do 1.5-0.2= 0.3 that´s the distance of the wall of the other triangle. Then you solve everything with Pitagoras theorem. You have 2 rectangle triangles.
B+alfa=45°
tan^-1(0.2/d)=B
tan^-1(1.3/d)=alfa
THEN:
tan^-1(0.2/d)+tan^-1(1.3/d)=45°
Now you have 3 ecs and 3 variables.
alfa,B and "d"
Answer:
y+-1/2x-1
Step-by-step explanation:
The line is negative
It rises one digit and runs 2
and it crosses though -1 on the y axis
Rectangle perimeter is 53 meters.
L = W + 2.3
To find the options of a perimeter, divide by 4.
= 13.25
So if this was a square, it would be 13.25 for both L and W but it's not.
Since the W has 2.3 meters more then the L, we do this.
13.25 + 2.3 = 15.55
13.25 - 2.3 = 10.95
Two of your sides equal 15.55, and the other two equal 10.95.
Hope this helps!
Distributive is the answer <span>
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