2 and 4 are both correct statements.
Length of the base = 8
Length of the hypotenuse = 17
The length of the third side ''
".
Using Pythagoras theorem, we have
(Perpendicular)² + (Base)² = (Hypotenuse)²
+ (8)² = (17)²
+ 64 = 289
= 289 - 64
= 225
= 
= 
Therefore, the length of the missing side is .
(15)² + (8)² = (17)²
225 + 64 = 289
289 = 289
L.H.S. = R. H. S.
Hence verified.
Answer:
I'm not good with the type of math on 3, so I'm going to answer 4. (P.S I don't know the question you're asking, so I'm going to assume you want to know the area and perimeter of the shapes.
Step-by-step explanation:
To solve number 4 I added the width of the 2 triangles to give me the width of the rectangle, so then 2 times 9 is 18. Then for the triangles. The formula for triangles is base times height divided by 2. So we add the areas of all shapes and we get: 18+6+24=48m. So the area for number 4 is 48 meters.
(hope this was your question)
The value of the digit is 90
