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2 years ago

Find the distance between points P(6, 5) and Q(2, 4) to the nearest tenth.

Mathematics

1 answer:

trasher [3.6K]2 years ago

3 0

Answer:

√10

Step-by-step explanation:

√(x2-x1)^2+(y2-y1)^2=√10

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Bananas cost $0.69 per pound. Which equation can be used to model the total cost, C, in dollars, of ,p, pounds of bananas

FromTheMoon [43]

The correct answer would be A. C = 0.69p.
This is the correct answer because the total cost of the bananas should equal 0.69 times each pound bought.
Hope this helped!

3 0

3 years ago

A sewing club used 48 feet of fabric to make 8 blankets. At this rate how many blankets can be made from 6 yards of fabric?

Scilla [17]

48f=8b
÷8 ÷8 (divided by 8)
6f=b
it takes 6 feet of fabric to make 1 blanket
6f=1b 3f=y
36f=6b
12y=6b

it takes 12 yards to make 6 blankets

7 0

3 years ago

Read 2 more answers

On the planet Joop, there are 6 gespils to every 14 vreels. If farmer

zzz [600]

Answer:

51 vreels

Step-by-step explanation:

Step 1: Given data

Ratio of gespils to vreels on the planet Joop: 6:14

Step 2: Calculate the number of gespils per 120 vreels

Elentine has 120 vreels on her rew farm. If there are 6 gespils every 14 vreels, the number of gespils is:

120 vreels × (6 gespils/14 vreels) ≈ 51 vreels

3 0

2 years ago

Based on this stock price model, what is the best prediction of what the price will do next?

andrew11 [14]

Go up. This is because the stock price is going up.

7 0

1 year ago

Use the graph of △ABC with midsegments DE, EF and DF. Show that EF is parallel to AC and that EF=1/2 AC

Vinvika [58]

According to the midsegment theorem, the midsegments are parallel to

and half the length of the opposite side.

The completed statement are as follows;

Because the slopes of $\overline{EF}$ and $\overline{AC}$ are both -4, $\overline{EF}$ ║ $\overline{AC}$

EF = $\underline{\sqrt{17}}$ and AC = $\underline{2 \cdot \sqrt{17} }$

Because $\underline{\sqrt{17} }$ = $\underline{\frac{1}{2} \cdot 2 \cdot \sqrt{17} }$ , $EF = \frac{1}{2} \cdot AC$

Reasons:

From the given graph of ΔABC, we have;

Coordinates of the points A, B, and C are; A(-5, 2), B(1, -2), and C(-3, -6)

The coordinates of the point D and E on $\mathbf{\overline{DE}}$ are; D(-4, -2), and E(-2, 0)

The coordinates of the point F is; F(-1, -4)

$Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\displaystyle Slope \ of \ line \ \overline{AC} = \mathbf{\frac{(-6) - 2}{-3 - (-5)} = \frac{-8}{2}} = -4$

$\displaystyle Slope \ of \ line \ \overline{EF} = \frac{0 - (-4)}{-2 - (-1)} = \frac{4}{-1} = -4$

$Length \ of \ segment,\ l = \sqrt{\left (x_{2}-x_{1} \right )^{2}+\left (y_{2}-y_{1} \right )^{2}}$

Length of EF = √((-1 - (-2))² + (-4 - 0)²) = √(17)

Length of AC = √((-3 - (-5))² + (-6 - 2)²) = √(4 × 17) = 2·√(17)

Therefore, we have;

Because the slope of $\mathbf{\overline {EF}}$ and $\mathbf{\overline {AC}}$ are both , -4, $\overline {EF}$ ║ $\overline {AC}$ . EF = $\underline{\sqrt{17}}$ , and AC

= $\underline{\frac{1}{2} \cdot 2 \cdot \sqrt{17}}$ ,. Because $\underline{\sqrt{17}}$ = $\underline{\frac{1}{2} \cdot 2 \cdot \sqrt{17}}$ , $EF =\mathbf{ \frac{1}{2} AC}$

Learn more about midsegment theorem of a triangle here:

brainly.com/question/7423948

8 0

2 years ago