A firecracker shoots up from a hill 140 feet high, with an initial speed of 100 feet per second. Using the formula H(t) = −16t2
+ vt + s, approximately how long will it take the firecracker to hit the ground?
A: Five seconds
B: Seven seconds
C: Nine seconds
D: 11 seconds
2 answers:
<span>H(t) = −16t^2 + vt + s
</span>
<span>H(t) = −16t^2 + 100t + 140
H(t) = 0 = </span><span>−16t^2 + 100t + 140
16t^2 - 100t -140 = 0
t = [100 +/- √ (100^2 -4(16)(-140) ) ] /(2(16))
t = 7.43 and t = - 1.18.
El que tiene sentido para la pregunta es t = 7.43 s.
Option B) 7 s (approximately)
</span>
Answer: it’s b, 7 seconds. Just took the test
Step-by-step explanation:
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