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Morgarella [4.7K]
3 years ago
12

A firecracker shoots up from a hill 140 feet high, with an initial speed of 100 feet per second. Using the formula H(t) = −16t2

+ vt + s, approximately how long will it take the firecracker to hit the ground?
A: Five seconds
B: Seven seconds
C: Nine seconds
D: 11 seconds
Mathematics
2 answers:
V125BC [204]3 years ago
6 0
<span>H(t) = −16t^2 + vt + s

</span>
<span>H(t) = −16t^2 + 100t + 140

H(t) = 0 = </span><span>−16t^2 + 100t + 140

16t^2 - 100t -140 = 0

t = [100 +/- √ (100^2 -4(16)(-140) ) ] /(2(16))

t = 7.43 and t = - 1.18.

El que tiene sentido para la pregunta es t = 7.43 s.

Option B) 7 s (approximately)


</span>
denis-greek [22]3 years ago
3 0

Answer: it’s b, 7 seconds. Just took the test

Step-by-step explanation:

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A=11+4b-4c. Solve for C.
devlian [24]
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The correct answer is option A

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