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Morgarella [4.7K]
3 years ago
12

A firecracker shoots up from a hill 140 feet high, with an initial speed of 100 feet per second. Using the formula H(t) = −16t2

+ vt + s, approximately how long will it take the firecracker to hit the ground?
A: Five seconds
B: Seven seconds
C: Nine seconds
D: 11 seconds
Mathematics
2 answers:
V125BC [204]3 years ago
6 0
<span>H(t) = −16t^2 + vt + s

</span>
<span>H(t) = −16t^2 + 100t + 140

H(t) = 0 = </span><span>−16t^2 + 100t + 140

16t^2 - 100t -140 = 0

t = [100 +/- √ (100^2 -4(16)(-140) ) ] /(2(16))

t = 7.43 and t = - 1.18.

El que tiene sentido para la pregunta es t = 7.43 s.

Option B) 7 s (approximately)


</span>
denis-greek [22]3 years ago
3 0

Answer: it’s b, 7 seconds. Just took the test

Step-by-step explanation:

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GuDViN [60]

Answer:

y =  \frac{1}{4}  \times  {2}^{x}  - 1

Step-by-step explanation:

Assuming the given logarithmic equation is

y =   \log_{2}( {4}{x }  - 4)

We interchange x and y to get:

x=   \log_{2}( {4}{y} - 4)

We solve for y now:

{2}^{x}  =  {4}{y}   - 4

We add 4 to both sides to get;

{2}^{x}  + 4 = 4y

Divide through by 4:

y =  \frac{1}{4}  \times  {2}^{x}  - 1

4 0
4 years ago
Which equation represents a circle with a center at (2, -7) and a radius of<br> 4 units?
Bezzdna [24]

Answer:

(x+3)^2+(y-5)^2=16

Step-by-step explanation:

3 0
3 years ago
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Could someone help me find the velocity of the object pls im stuck
Mila [183]

Answer:

10 m/s

Step-by-step explanation:

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You can take any point on the line to calculate velocity.

Lets take t=1s

At t=1, position=10m

velocity= 10m/1s

=10 m/s

You can take any other point too, velocity will remain same.

For eg.

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5 0
3 years ago
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Solve that for me :)
gavmur [86]

Answer:

2/5

Step-by-step explanation:

Out of the available options on the spinner, only 1 and 5 are factors of 25.

=> Outcomes = 2

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P (factor of 25) = 2/5

Hope it helps.

5 0
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Please help !!
shutvik [7]

Given:

The limit problem is:

\lim_{x\to 3}(x^2+8x-2)

To find:

The limit of the function by using direct substitution.

Solution:

We have,

\lim_{x\to 3}(x^2+8x-2)

Applying limit, we get

\lim_{x\to 3}(x^2+8x-2)=(3)^2+8(3)-2

\lim_{x\to 3}(x^2+8x-2)=9+24-2

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\lim_{x\to 3}(x^2+8x-2)=31

Therefore, the correct option is D.

4 0
3 years ago
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