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igomit [66]
3 years ago
8

WHICH EXPRESSION IS EQUIVALENT TO (3X5+8X3)-(7X2-6X3)

Mathematics
1 answer:
Anestetic [448]3 years ago
7 0
(3\times5+8\times3)-(7\times2-6\times3) \\ =(15+24)-(14-18) \\ =39-(-4) \\ =39+4 \\ =43 \\  \\ ANSWER = 43
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(1 point)
Alex73 [517]

Answer:

had to add it here bit. ly  3a7A8h

Step-by-step explanation:

7 0
3 years ago
What is algebra? Why does algebra used for?
Natalka [10]
Algebra is math where you find the values of symbols, variables, etc. It is used to find the value of something you don't know.
7 0
3 years ago
Read 2 more answers
WILL MARK BRAINLIEST
forsale [732]

Answer:

-3 x 10

Step-by-step explanation:

the first one is 5

4 0
3 years ago
Can somebody help me? With those three problems please
s2008m [1.1K]

Answer:

15. x = 8

16. m<V = 103°

17. x = 14

Step-by-step explanation:

15. The figure given is quadrilateral. Sum of interior angles of a quadrilateral = 360°

Therefore:

(10x + 6) + (13x - 2) + (8x - 1) + (180 - 71) = 360

Solve for x

10x + 6 + 13x - 2 + 8x - 1 + 109 = 360

Add like terms

31x + 112 = 360

Subtract 112 from each side

31x = 248

Divide both sides by 31

x = 8

16. The polygon is a hexagon. Sum of interior angles of a hexagon = 720. Therefore:

90 + (7x + 3) + 128 + (5x + 8) + 111 + (9x - 19) = 720

Solve for x

90 + 7x + 3 + 128 + 5x + 8 + 111 + 9x - 19 = 720

Add like terms

321 + 21x = 720

Subtract 321 from each side

21x = 399

Divide both sides by 21

x = 19

m<V = 5x + 8

Plug in the value of x

m<V = 5(19) + 8 = 95 + 8

m<V = 103

17. The polygon is a regular pentagon. This means each of the angles measures 108°. The sum of the interior angles all together is 540.

Therefore:

(9x - 18) = 108

Solve for x

9x - 18 = 108

Add 18 to both sides

9x = 126

Divide both sides by 9

x = 14

7 0
3 years ago
4/5-11/15 can you help me?
Ainat [17]

Answer:

\frac{1}{15} is the answer.

Step-by-step explanation:

\frac{4}{5} - \frac{11}{15}

Change the denominators to 15.

\frac{12}{15} - \frac{11}{15}

12 - 11 = 1.

= \frac{1}{15}

5 0
2 years ago
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