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natta225 [31]
3 years ago
13

What are two terms that add together to make -7 and that also multiply to make 6

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
7 0

Answer:

<em>These two numbers are -1 and -6 respectively.</em>

Step-by-step explanation:

Suppose first number is x and the second number is y.

Then according to question-

( x + y ) = -7 ..............................(i)

( x × y ) =  6 ................................(ii)

As we know that-

( x - y )^{2} = ( x + y )^{2} - 4 x y   .......................(iii)

Now, Putting values of equation (i), (ii)  in equation (iii)-

We get,

( x - y )^{2} = ( - 7 )^{2}   - 4 × 6

( x - y )^{2}  = 49 - 24

( x - y )^{2}  = 25

( x - y ) = \sqrt{25}

( x - y ) = 5..........................(iv)

After adding equation (i) and (iv)-

( x + y ) = -7

<u>( x - y ) =  5</u>

<u>2 x = -2</u>

x = -2 /2

<em>x = -1</em>

Now put x = -1 in equation (i)-

We get,

y = -7 - x

y = -7 - (- 1)

y = - 7 + 1

<em>y = -6</em>

<em></em>

     <em>  Hence the both numbers x and y are -1, -6 respectively.</em>

neonofarm [45]3 years ago
4 0

Answer:

-6 and -1

Step-by-step explanation:

When you add

-6+(-1)

-6-1

-7.

When you multiply

-6x-1

6.

PLEASE MARK AS BRAINLIEST.

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Answer is a.
Due to BIDMAS/BODMAS
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If f(x) = 5x + 4, which of the following is the inverse of (fx)?​
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see explanation

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

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32​% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a
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Answer:

a) P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

b) P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668

c) P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816

Step-by-step explanation:

1) Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

2) Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=10, p=0.32)

The probability mass function for the Binomial distribution is given as:

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Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

Part b

P(X> 2)=1-P(X\leq 2)=1-[P(X=0)+P(X=1)+P(X=2)]

P(X=0)=(10C0)(0.32)^0 (1-0.32)^{10-0}=0.0211  

P(X=1)=(10C1)(0.32)^1 (1-0.32)^{10-1}=0.0995

P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668

Part c

P(2 \leq x \leq 5)=P(X=2)+P(X=3)+P(X=4)+P(X=5)

P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

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P(X=4)=(10C4)(0.32)^4 (1-0.32)^{10-4}=0.218

P(X=5)=(10C5)(0.32)^5 (1-0.32)^{10-5}=0.123

P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816

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