Answer:
a. 2100
b. 2199
Explanation:
GIven that:
The file size = 1000 MB
The payload size is = 100 bytes
The negotiated window size is = 1000 bytes.
This implies that the sliding window can accommodate maximum number of 10 packets
The sender receives an ACK 1200 from the receiver.
Total byte of the file is :
1000 MB = 1024000000 bytes
a.
Sender receives an ACK 1200 from the receiver but still two packets are still unacknowledged
=1200 + 9 * 100
= 1200 + 900
= 2100
b. What is the last byte number that can be sent without an ACK being sent by the receiver?
b. Usually byte number starts from zero, in the first packet, the last byte will be 99 because it is in 1000th place.
Thus; the last byte number send is :
= 1200 + 10 *100 -1
= 1200 + 1000-1
= 1200 + 999
= 2199
Answer:
c) Access Control.
Explanation:
The term which describes the security domain best that relates to how the data is valued and classified is Access Control.
Access Control :It is the restriction of access of a resource or a place that is selective.Permission to access a resource is called authorization.It is an important term in the field of information security and physical security.
It is okay to modify photos digitally to improve their appearance as long as it doesn't show what they aren't producing.
<h3>What is Advertisement?</h3>
This is the act of persuading people to buy goods and services and is usually done with the aid of the media.
Pictures are usually taken which have to be in the best shape and quality in order to entice people to buy the goods thereby bringing about higher sales and profit for the company.
Read more about Advertisement here brainly.com/question/1020696
Answer:
function [Area,Perimeter,L]=f_circle(x)
% Area: pi*x^2 area of circle with radius x
% Perimeter: 2*pi*x perimeter length of circle with radius x
% x can be a vector
minargs=1;maxargs=1;narginchk(minargs,maxargs); % only 1 input accepted
if ~isequal('double',class(x)) 5 input has to be type double
disp('input type not double');
return;
end
Area=pi*x.^2;
Perimeter=2*pi*x;
end