-5.25 to the nearest tenth is -5.3.
Given:
1st fraction - 7/24
2nd fraction - 34/48
Rules in dividing fractions:
1) Get the reciprocal of the 2nd fraction.
34/48 becomes 48/34
2) Multiply the 1st fraction to the reciprocal of the 2nd fraction
7/24 * 48/34 = 7*48 / 24*34 = 336/816
3) Simplify the fraction
336/816 ⇒ 112/272 ⇒ 56/136 ⇒ 14/34 ⇒ 7/17
336 ÷ 3 = 112
816 ÷ 3 = 272
112 ÷ 2 = 56
272 ÷ 2 = 136
56 ÷ 4 = 14
136 ÷ 4 = 34
14 ÷ 2 = 7
34 ÷ 2 = 17
7/24 ÷ 35/48 = 7/17
For a known standard deviation, the confidence interval for sample size = n is
![(x-z \frac{ \sigma }{ \sqrt{n}},x+x \frac{ \sigma }{ \sqrt{n} } )](https://tex.z-dn.net/?f=%28x-z%20%5Cfrac%7B%20%5Csigma%20%7D%7B%20%5Csqrt%7Bn%7D%7D%2Cx%2Bx%20%5Cfrac%7B%20%5Csigma%20%7D%7B%20%5Csqrt%7Bn%7D%20%7D%20%20%29)
where
x = average
n = sample size
![\sigma](https://tex.z-dn.net/?f=%20%5Csigma%20)
= stad. deviation
z = contant that reflects confidence interval
Let a = x
Let b =
![z \frac{ \sigma }{ \sqrt{n} }](https://tex.z-dn.net/?f=z%20%5Cfrac%7B%20%5Csigma%20%7D%7B%20%5Csqrt%7Bn%7D%20%7D%20)
From the given information,
a - b = 0.432 (1)
a + b = 0.52 (2)
Add (1) and (2): 2a = 0.952 => a = 0.476
Subtract (2) from (1): -2b = -0.088 => b = 0.044
Therefore, the confidence interval may be written as
(0.476 - 0.044, 0.476 + 0.044), or as
(0.476
![\pm](https://tex.z-dn.net/?f=%20%5Cpm%20)
0.044)
Answer:
Step-by-step explanation:
8/-36
-0.222222...
Area of a triangle = (1/2)(base)(height).
Here, 2(area of triangle) = (base)(height), so base = 2(area of triangle) / height.
For this particular triangle, the base is 2(138 mm^2) / (12 mm), or base = 23 mm