X square-11x-26 of algebraic expressions

Calculate the total budget and then fill in the missing percentages. You will use some of the answers given more than once. Tota

lutik1710 [3]

Total budget = $13,500

Donations = 12%

Taxes = 12%

Food = 26%

Clothing = 20%

Housing = 10%

and the rest are 5 %

6 0

2 years ago

Read 2 more answers

Complete the TABLE of values for x+y=6.

kvasek [131]

Answer:

X Y

-2 8

-1 7

0 6

1 5

2 4

3 3

Step-by-step explanation:

We have the equation: x+y=6

We want to get this in the form: y=mx+b (or in this case y=x+b)

To do this we need y to be positive and by itself

So we subtract y from both sides and divide by -1 (we divide by -1 because otherwise y would be negative and that does not fit our template of y=x+b)

Doing this we have

-x+6=y

From here we just plug in numbers -2 to 3 which I will assume you know how to do

X Y

-2 8

-1 7

0 6

1 5

2 4

3 3

6 0

2 years ago

Consider randomly selecting a student at a large university, and let A be the event that the selected student has a Visa card an

ziro4ka [17]

Answer:

1) is not possible

2) P(A∪B) = 0.7

3) 1- P(A∪B) =0.3

4) a) C=A∩B' and P(C)= 0.3

b) P(D)= 0.4

Step-by-step explanation:

1) since the intersection of 2 events cannot be bigger than the smaller event then is not possible that P(A∩B)=0.5 since P(B)=0.4 . Thus the maximum possible value of P(A∩B) is 0.4

2) denoting A= getting Visa card , B= getting MasterCard the probability of getting one of the types of cards is given by

P(A∪B)= P(A)+P(B) - P(A∩B) = 0.6+0.4-0.3 = 0.7

P(A∪B) = 0.7

3) the probability that a student has neither type of card is 1- P(A∪B) = 1-0.7 = 0.3

4) the event C that the selected student has a visa card but not a MasterCard is given by C=A∩B' , where B' is the complement of B. Then

P(C)= P(A∩B') = P(A) - P(A∩B) = 0.6 - 0.3 = 0.3

the probability for the event D=a student has exactly one of the cards is

P(D)= P(A∩B') + P(A'∩B) = P(A∪B) - P(A∩B) = 0.7 - 0.3 = 0.4

3 0

2 years ago

At Burnt Mesa Pueblo, archaeological studies have used the method of tree-ring dating in an effort to determine when prehistoric

Zanzabum

Answer:

a) (1215, 1297)

b) (1174, 1338)

c) (1133, 1379)

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1256

Standard Deviation, σ = 41

Empirical Rule:

Also known as 68-95-99.7 rule.
It states that almost all the data lies within three standard deviation for a normal data.
About 68% of data lies within 1 standard deviation of mean.
About 95% of data lies within two standard deviation of mean.
About 99.7% of data lies within 3 standard deviation of mean.

a) range of years centered about the mean in which about 68% of the data lies

$\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)$

68% of data will be found between 1215 years and 1297 years.

b) range of years centered about the mean in which about 95% of the data lies

$\mu \pm 2(\sigma)\\=1256 \pm 2(41)\\=1256 \pm 82\\=(1174, 1338)$

95% of data will be found between 1174 years and 1338 years.

c) range of years centered about the mean in which about all of the data lies

$\mu \pm 3(\sigma)\\=1256 \pm 3(41)\\=1256 \pm 123\\=(1133, 1379)$

All of data will be found between 1133 years and 1379 years.

3 0

3 years ago

57.

barxatty [35]

Answer:

$5.70

Step-by-step explanation:

→ Find the total amount they needed to pay

11.40 × 2 = 22.80

→ Divide the total by 4

22.80 ÷ 4 = $5.70

6 0

2 years ago

X square-11x-26 of algebraic expressions​

X square-11x-26 of algebraic expressions