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Slav-nsk [51]
3 years ago
7

What value should go in the empty boxes to complete the calculation for finding the product of 0.61 × 0.45? Both numbers are the

same; however, only input the number one time in your answer.
i need help TuT
Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
6 0

0.2745 I believe... because 0.61 times 0.45 gives you that answer....

Luda [366]3 years ago
5 0

Answer

Its a lil confusing lol

               0.61

           x 0.45

         ----------

              305

           + 2440

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The value of y varies directly with x, and y = −10 when x = 40. Identify the value of y when x = −5.
s2008m [1.1K]
-10/40 = y / -5
cross multiply
(40)(y) = (-5)(-10)
40y = 50
y = 50/40
y = 5/4 <===
8 0
3 years ago
Read 2 more answers
6th grade math help me please !
antiseptic1488 [7]

First we have to figure out how much 3 bags cost using the total cost of $8.25

That means. we would do 8.25/3 and 8.25 divide by 3 equals 2.75.

Now we know that each bag costs approximately $2.75

All we have to do now is multiply 2.75 by 4 to get the cost for the total of 4  bags.

4 times 2.75 is exactly 11 dollars, if might change if theres tax.

But, the answer would be 4 bags costs $11.

6 0
3 years ago
URGENT HELP ME PLEASE
Trava [24]

Answer:

(a)\log_3(\dfrac{81}{3})=3

(b)\log_5(\dfrac{625}{25})=2

(c)\log_2(\dfrac{64}{8})=3

(d)\log_4(\dfrac{64}{16})=1

(e)\log_6(36^4)=8

(f)\log(100^3)=6

Step-by-step explanation:

Let as consider the given equations are \log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?.

(a)

\log_3(\dfrac{81}{3})=\log_3(27)

\log_3(\dfrac{81}{3})=\log_3(3^3)

\log_3(\dfrac{81}{3})=3        [\because \log_aa^x=x]

(b)

\log_5(\dfrac{625}{25})=\log_5(25)

\log_5(\dfrac{625}{25})=\log_5(5^2)

\log_5(\dfrac{625}{25})=2        [\because \log_aa^x=x]

(c)

\log_2(\dfrac{64}{8})=\log_2(8)

\log_2(\dfrac{64}{8})=\log_2(2^3)

\log_2(\dfrac{64}{8})=3        [\because \log_aa^x=x]

(d)

\log_4(\dfrac{64}{16})=\log_4(4)

\log_4(\dfrac{64}{16})=1        [\because \log_aa^x=x]

(e)

\log_6(36^4)=\log_6((6^2)^4)

\log_6(36^4)=\log_6(6^8)

\log_6(36^4)=8            [\because \log_aa^x=x]

(f)

\log(100^3)=\log((10^2)^3)

\log(100^3)=\log(10^6)

\log(100^3)=6            [\because \log10^x=x]

5 0
3 years ago
Expand (2 + a)9 using Pascal’s triangle.
Natalija [7]

Answer:

Step-by-step explanation:

The Pascal triangle is used to determine the coefficients of the terms when we expand the expression.

                                             1                                (A + B) ^ 0 = 1

                                         1       1                            (A +B ) ^ 1 = 1A + 1B

                                   1          2        1          (A+ B) ^ 2 = 1A^2 + 2 AB + 1B^2

By extending the triangle, you will get the 9th row, which is your expression, of the coefficients. that is

1          9       36    84    126    126    84    36    9    1

Now, fill in AB in the gaps.

1AB + 9 AB + 36AB + 84AB + 126AB + 126AB +84AB + 36AB + 9AB + 1AB

Next, you need to go from the left to fill out the exponent of A and it will go down from 9 (the exponent of the whole thing) . That is

1A^9B+9A^8B+36A^7B+84A^6B+126A^5B+126A^4B+84A^3B+36A^2B+9A^1B+1A^0B

Next will be the exponent of B. this time, you go from the right and do the same with A. You can go from the left also, but go up from 0 to 9 for the exponent of B

1A^9B^0+9A^8B^1+36A^7B^2+84A^6B^3+126A^5B^4+126A^4B^5+84A^3B^6+36A^2B^7+9A^1B^8+1A^0B^9

The last step is just to simplify the A^0=1 and B^0 =1 at the first and the last terms.

A^9+9A^8B^1+36A^7B^2+84A^6B^3+126A^5B^4+126A^4B^5+84A^3B^6+36A^2B^7+9A^1B^8+B^9

Hope you can learn the method

5 0
3 years ago
Jamal earns $2200 each month and has a car payment of $264. What percent of his income goes toward his car payment?
finlep [7]

2200 / 264 = 8.333333-

Round the answer, which is 8.

So, your answer is A. 8%

3 0
3 years ago
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