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qaws [65]
3 years ago
6

You buy 3 tickets for $ 48 total for the jazz concert on Friday night. Your friend buys 2 tickets for $36 total for the jazz con

cert on Saturday night. Your brother collected $96 from his friends to buy 6 tickets. Which night can they go to the concert? Did they buy the less expensive tickets? Explain
Mathematics
1 answer:
yKpoI14uk [10]3 years ago
5 0

Answer:

Friday night.

Less expensive.

Step-by-step explanation:

Cost of  1 ticket on  Friday = 48/3 = $16.

Cost on Saturday =   36 / 2 = $18.

Now 96 / 6 = $16 so the brother and his friends will have to go to the Friday concert. From the above costs we see that they did buy the less expensive ticket.

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Which expression can be used to find the volume of the sphere?
Kryger [21]

Answer:

They used 3.14 for pi:

V=\frac{4}{3} \pi r^3

V=\frac{4}{3} (3.14)(5)^3

Step-by-step explanation:

V=\frac{4}{3}\pi r^3 is the volume of a sphere with radius r.

I think that is the diameter given in the picture.

The radius is half the diameter.

So the radius is 5 since the diameter is 10.

Plug in this gives you:

V=\frac{4}{3} \pi (5)^3

4 0
3 years ago
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JK⎯⎯⎯⎯⎯ is dilated by a scale factor of n with the origin as the center of dilation, resulting in the image J′K′⎯⎯⎯⎯⎯⎯⎯. The slo
adelina 88 [10]
Its not A but i might be B C D
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3 years ago
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A brick layer is able to set 2.5 breaks in one minute how many bricks can you set an eight hours
frozen [14]

Answer:

<h2> In 8 hours he will set 1200 bricks</h2>

Step-by-step explanation:

In this problem, we are expected to estimate the number of bricks he can set in 8 hours.

let us convert hours to minutes we have

60 min make 1 hour

x min make 8 hours

cross multiply

x= 60*8

x= 480 min

We are assuming the same rate with which he sets 2.5 brick is the same as the rate with which he will set bricks for the 8 hours windows

so if the bricklayer sets

2.5 bricks in 1min

y bricks in 480 min

Cross multiply we have

y=2.5*480

y= 1200  bricks

hence in 8 hours, he will set 1200 bricks

5 0
3 years ago
Please help me with this
Ivan
800/560
10/7

Your answer is 1 3/7 pounds per dollar

hope it helps
6 0
3 years ago
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5^(-x)+7=2x+4 This was on plato
Setler79 [48]

Answer:

Below

I hope its not too complicated

x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}

Step-by-step explanation:

5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}

Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}

\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x

\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}

3 0
3 years ago
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