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AveGali [126]
3 years ago
8

Periodic rate can be computed using this formula

Mathematics
1 answer:
Damm [24]3 years ago
3 0

Answer & Explanation:

First, divide the nominal rate by the number of compounding periods. The result is the periodic rate. Now add this number to 1 and take the sum by the power of the number of compounding interest rates. Subtract 1 from the product to get the effective interest rate.

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Write two decimals that are equivalent to the given decimal.<br> 0.60 and 0.9
miskamm [114]
I'm pretty sure it's 5.4
6 0
3 years ago
If f(x) = 2x^2 + 2, find f(5)
zlopas [31]

Well, following the order of PEMDAS, I got choice B. 52

For instance, when you plug in 5 for x, you get F(5)=2(5)^2+2.

Moreover, following PEMDAS, you're supposed to solve what's inside the parenthesis, but since there is no operation going on inside the parenthesis, then you simple move on to the exponent.

In this case, you square the number 5, which gives you F(5)=2(25)+2

After that, you Multiply (letter M in PEMDAS). This results in F(5)=50+2.

Finally, you add them, which results in F=52.


By the way, I noticed a mistake in your work. When multiplying 2 by 5, the answer is 10, not 20.

Anyway, hope this helped! :-)  

8 0
3 years ago
Hailey earned $90 for working 12 hours. How much can she earn for working 29 hours
Afina-wow [57]

Answer:

She will make 217.50 for 29 hours

Step-by-step explanation:

We can find the rate per hour by dividing the money by the number of hours

90/12 =7.5 per hour

She makes 7.50 per hour

If she works 29 hours

Money = rate * hours

           = 7.5 * 29

           =217.50

She will make 217.50 for 29 hours

8 0
3 years ago
Read 2 more answers
A regular hexagon is rotated about its center. By which angle could the hexagon be rotated so that it is mapped onto itself?
Sauron [17]

Answer: 60

Step-by-step explanation:

5 0
3 years ago
A 12-ounce bottle of shampoo costs $2.79. A 16-ounce bottle of shampoo costs $3.25. Which statement is true?
JulsSmile [24]
That would be C! Good Luck!
6 0
3 years ago
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