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AveGali [126]
3 years ago
8

Periodic rate can be computed using this formula

Mathematics
1 answer:
Damm [24]3 years ago
3 0

Answer & Explanation:

First, divide the nominal rate by the number of compounding periods. The result is the periodic rate. Now add this number to 1 and take the sum by the power of the number of compounding interest rates. Subtract 1 from the product to get the effective interest rate.

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How many 1/3 liters are in 4 2/3 liters
jonny [76]

Answer:

14

Step-by-step explanation:

This is a division problem.

We want to find how many 1/3 liters are in 4⅔ liters.

We divide to obtain:

\frac{4 \frac{2}{3} }{ \frac{1}{3} }

Or

4 \frac{2}{3}  \div  \frac{1}{3}

Convert to improper fraction.

\frac{14}{3}  \div  \frac{1}{3}

\frac{14}{3}  \times  \frac{3}{1}

This simplifies to

14

Therefore there are fourteen ⅓ liters in 4⅔ liters

5 0
3 years ago
(6n-6)(n-1)<br><br> simplify by multiplying
lora16 [44]
6n2 - 6n - 6n + 6
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3 0
3 years ago
Plz help<br><br> Simplify 6(x + 4)
saw5 [17]

Final Answer: 6x + 24

Steps/Reasons:

Question: Simplify 6(x + 4)

<u>Step 1</u>: Expand by distributing the terms.

6x+ 6 × 4

<u>Step 2</u>: Simplify 6 × 4 to 24.

6x + 24

~I hope I helped you :)~

8 0
3 years ago
Read 2 more answers
HELP!!!!!!!!!!!!!!!!!!!!!!!!
Ksivusya [100]

Answer:

Step-by-step explanation:

7 0
3 years ago
A probability model includes P(red) = 27 2 7 and P(blue) = 314 3 14 . Which of the following probabilities could complete the mo
Ivahew [28]

Answer:

(b)\ P(Green) = \frac{3}{8} ; P(Yellow) = \frac{1}{8}

(c)\ P(Green) = \frac{1}{4} ; P(Yellow) = \frac{1}{4}

Step-by-step explanation:

Given

P(Red) = \frac{2}{7}

P(Blue) = \frac{3}{14}

Required

Which completes the model

Let the remaining probability be x.

Such that:

P(Red) +  P(Blue) + x = 1

Make x the subject

x = 1 - P(Red) - P(Blue)

So, we have:

x = 1 - \frac{2}{7} - \frac{3}{14}

Solve

x = \frac{14 - 4 - 3}{14}

x = \frac{7}{14}

x = \frac{1}{2}

This mean that the remaining model must add up to 1/2

(a)\ P(Green) = \frac{2}{7} ; P(Yellow) = \frac{2}{7}

P(Green) + P(Yellow)= \frac{2}{7} + \frac{2}{7}

Take LCM

P(Green) + P(Yellow)= \frac{2+2}{7}

P(Green) + P(Yellow)= \frac{4}{7}

This is false because: \frac{4}{7} \ne \frac{1}{2}

(b)\ P(Green) = \frac{3}{8} ; P(Yellow) = \frac{1}{8}

P(Green) + P(Yellow)= \frac{3}{8} + \frac{1}{8}

Take LCM

P(Green) + P(Yellow)= \frac{3+1}{8}

P(Green) + P(Yellow)= \frac{4}{8}

P(Green) + P(Yellow)= \frac{1}{2}

This is true

(c)\ P(Green) = \frac{1}{4} ; P(Yellow) = \frac{1}{4}

P(Green) + P(Yellow)= \frac{1}{4} + \frac{1}{4}

Take LCM

P(Green) + P(Yellow)= \frac{1+1}{4}

P(Green) + P(Yellow)= \frac{2}{4}

P(Green) + P(Yellow)= \frac{1}{2}

This is true

Other options are also false

6 0
3 years ago
Read 2 more answers
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