Write in slope-intercept form an equation of the line that passes through the given points. When the points are, (-1,4) and (3,8
)...... please help.
2 answers:
I find it easiest to start with the 2-point form of the equation of a line.
y = (y₂-y₁)/(x₂-x₁)*(x-x₁) +y₁
where the given points are (x₁, y₁) and (x₂, y₂).
Substituting the given numbers, you have
y = (8 -4)/(3 -(-1))*(x -(-1)) +4
y = 4/4(x +1) +4
y = x +5
The desired slope-intercept form of the equation for the line is ...
y = x + 5
y = (y₂-y₁)/(x₂-x₁)*(x-x₁) +y₁
where the given points are (x₁, y₁) and (x₂, y₂).
Substituting the given numbers, you have
y = (8 -4)/(3 -(-1))*(x -(-1)) +4
y = 4/4(x +1) +4
y = x +5
The desired slope-intercept form of the equation for the line is ...
y = x + 5
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