Let n be the larger integer and n-2 be the smaller integer.
n² - (n - 2)²
= n² - (n - 2)(n - 2)
= n² - (n² - 4n - 4)
= n² - n² + 4n + 4
= 4n + 4
= 4(n + 1)
No matter what value n is, it will always be a multiple of 4.
Answer is 0. Use PEMDAS. Trust the process
Answer:
two hundredths
Step-by-step explanation:
6 is in the ones place. 3 is in the tenths place. 2 is in the hundredths place
5 is in the thousandths place.
Answer: 8
Step-by-step explanation:
6x-3=45
6x=48
x=8
Answer:
i d k cuz they r du.mb???
Step-by-step explanation:
have a nice day :) :) :)
