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8_murik_8 [283]
3 years ago
10

Which factor below would be least likely to cause a mutation in the cells of an organism. Select one: a. Radiation b. Smoking c.

Sound wave d. Chemical pollution
Chemistry
1 answer:
Nutka1998 [239]3 years ago
3 0

Answer:

The correct option is;

c. Sound wave

Explanation:

The given options effect on mutation are given as follows;

a. Radiation

Radiation such as ultraviolet light and gamma radiation, which are electromagnetic waves, cause mutations by causing the formation of free radicals within an organism's cell resulting in the mutation characteristic effects

b. Smoking of tobacco has mutagenic effects due to the presence of several carcinogenic compounds in cigarettes

c. Sound wave is a form of mechanical wave and has no chemical effects on the chemistry of an organism and therefore does not cause mutation in cells

d. Chemical pollution can contain carcinogenic compounds that can cause mutations in the cells of organisms.

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50 POINTS!!!!!!
sattari [20]
Remember that enzymes always accelerate chemical equations, depending on what the enzyme is consisted of. As the enzymes are burned the reaction or amount of chemical reactions decreases.
4 0
3 years ago
A rigid tank contains 0.66 mol of oxygen (O2). Find the mass of oxygen that must be withdrawn from the tank to lower the pressur
dsp73

Answer:

12.8 g of O_{2} must be withdrawn from tank

Explanation:

Let's assume O_{2} gas inside tank behaves ideally.

According to ideal gas equation- PV=nRT

where P is pressure of O_{2}, V is volume of O_{2}, n is number of moles of O_{2}, R is gas constant and T is temperature in kelvin scale.

We can also write, \frac{V}{RT}=\frac{n}{P}

Here V, T and R are constants.

So, \frac{n}{P} ratio will also be constant before and after removal of O_{2} from tank

Hence, \frac{n_{before}}{P_{before}}=\frac{n_{after}}{P_{after}}

Here, \frac{n_{before}}{P_{before}}=\frac{0.66mol}{43atm} and P_{after}=17atm

So, n_{after}=\frac{n_{before}}{P_{before}}\times P_{after}=\frac{0.66mol}{43atm}\times 17atm=0.26mol

So, moles of O_{2} must be withdrawn = (0.66 - 0.26) mol = 0.40 mol

Molar mass of O_{2} = 32 g/mol

So, mass of O_{2} must be withdrawn = (32\times 0.40)g=12.8g

7 0
3 years ago
Rubidium has two naturally occurring isotopes, rubidium -85 ( atomic mass = 84.9118 amu; abundance = 72.15%) and rubidium -87 (a
son4ous [18]

Answer:

The answer to your question is: 85.458 amu

Explanation:

data

Rubidium-85   A = 84.9118 amu   abundance = 72.15%  

Rubidium - 87  A = 86.9092 amu abundance = 27.85%

Atomic weight = ?

Atomic weight = 84.9118(0.7215) + 86.9092(0.2785)

Atomic weight = 61.2538 + 24.2042

Atomic weight = 85.458 amu

6 0
4 years ago
A substance that is made up of two or more elements is called ____.
Art [367]
A compound or a mixture.
If it is two or more elements are mixed, it is a mixture. If two or more elements are chemically reacted, it is a compound ( example FeS)
Hope this helps.  
6 0
3 years ago
N2 +3H2 → 2NH3 What volume of ammonia at STP is produced if 30.0 g of nitrogen gas is reacted with an excess of hydrogen gas?
WARRIOR [948]

Answer:

V= 48L

Explanation:

Moles of N2 = m/M = 30/28= 1.07moles

From the equation of reaction

N2 +3H2 → 2NH3

1mole of N2 produces 2mole of NH3

Hence

1.07moles will produce 1.07×2= 2.14 moles

At STP, 1mole occupy 22.4L

Hence volume of N2 produced = 2.14×22.4= 48 L

3 0
4 years ago
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