<span>In this expression, the variable ’t’ stands in for any possible value of seconds. Therefore, since you know how long it takes the object to fall in seconds, you can put this into the expression. 16 x (4^2) = 256. The distance is 256ft.</span>
5k^2 = 25 ^ 3 = 15625
5k^6 = 15625
Hope this helps
Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
The formula for the volume of a cone is V = πr²h
÷3
You are solving for the height, h.
V = 338 cm³ and r = 6 cm
338 = π(6)²h÷3
338 = π36h÷3
338 = π12h
28.16 = πh
8.965 = h
The height of the cone is around 9 cm.
