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Evgen [1.6K]
2 years ago
15

Select all the expressions that equal 6^-10

Mathematics
2 answers:
amm18122 years ago
6 0

Answer:

we need a  list first

Step-by-step explanation:

Firdavs [7]2 years ago
5 0
I can’t solve because you did not list any
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MrRissso [65]
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3 0
3 years ago
Read 2 more answers
Let f be defined as shown.<br> What is f^-1(8)?
Gnoma [55]

Answer:

From the picture when the input of f(x) is 6 the output is 8

So it's just the reverse f^-1(8) when the input is 8 the output is 6

So f^-1(8) = 6

Hope this helps you

4 0
3 years ago
The number of coffee shops in a certain country can be modeled by the quadratic function ​f(x)105x²+680x+4296, where​ f(x) is th
grigory [225]

A. X is the number of years after 2000

2006-200 = 6 years.

Replace x with 6 and solve:

105(6)^2 + 680(6) + 4296 = 12,156


Answer for part a: 12,156


Answer for part B.
There was just over 12,000 in 6 years , to get to 21,500 would be a little over 9,000 more 9/12 = 0.75

6 years x .75 = 4.5 years


6 + 4.5 = 10.5 years round to 10 years for estimating purposes


Answer for part b: about 10 years

7 0
2 years ago
The number of registered vehicles on the road in a country is constantly increasing. In​ 2009, there were approximately 270 mill
spin [16.1K]

The Answer to your problem is:

270000000 x 4%

Answer:

10800000

3 0
3 years ago
Two positive, consecutive, odd integers have a product of 143.
zhannawk [14.2K]

Answer:

<em>The answer is 13</em>

Step-by-step explanation:

Two positive and consecutive old numbers are x and x - 2.

=> x(x - 2) = 143

=> x^2 - 2x - 143 = 0

=> x^2 + 11x - 13x - 143 = 0

=> x(x + 11) - 13(x + 11) = 0

=> (x + 11)(x - 13) = 0

=>  x = -11 (invalid)

or x = 13 (valid), the remaining number is 13 - 2 = 11

=> The two numbers are 11 and 13, and the greater number is 13.

Hope this helps!

:)

7 0
3 years ago
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