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AlladinOne [14]

3 years ago

9

Clara lends half her collection of formal attires to her sister, Susan. Clara then buys four more attires. If she has 12 attires

now, how many attires did Clara had initially?
Write the equation to be used to solve this equation.

1 answer:

nirvana33 [79]3 years ago

5 0

Answer:

i think 4 attires

Step-by-step explanation:

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“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor

Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

$C=2\pi r$

<u><em>Find the radius of the sphere with a 5.50-meter circumference</em></u>

For $C=5.50\ m$

assume

$\pi =3.14$

substitute and solve for r

$5.50=2(3.14)r$

$r=5.50/[2(3.14)]=0.88\ m$

<u><em>Find the radius of the sphere with a 7.85-meter circumference</em></u>

For $C=7.85\ m$

assume

$\pi =3.14$

substitute and solve for r

$7.85=2(3.14)r$

$r=7.85/[2(3.14)]=1.25\ m$

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

$SA=4\pi r^{2}$

<u><em>Find the surface area of sphere with a 5.50-meter circumference</em></u>

For $r=0.88\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(0.88)^{2}$

$SA=9.73\ m^{2}$

<u><em>Find the surface area of sphere with a 7.85-meter circumference</em></u>

For $r=1.25\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(1.25)^{2}$

$SA=19.63\ m^{2}$

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

<u><em>Find the cost of sphere with a 5.50-meter circumference</em></u>

$9.73*(92)=\$895.16$

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

<u><em>Find the cost of sphere with a 7.85-meter circumference</em></u>

$19.63*(92)=\$1,805.96$

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

6 0

3 years ago

These two polygons are similar.

Nady [450]

9

yea........ hi how you doinn

4 0

2 years ago

DETERMINE<br> THE<br> DIFFERENCE<br> BETWEEN-2/5 and -0.75

timama [110]

Answer:

0.3

Step-by-step explanation:

Convert -2/5 into a decimal.

-0.4.

Then subtract the two.

-0.4-(-0.75)

-0.4+(+0.75)

0.3

6 0

3 years ago

What is an appropriate scale to graph a credit of $35 and a debit of $40?Explain your reasoning

miss Akunina [59]

A bar graph since I'm only going up by fives it's easy to show as a bar graph

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3 years ago

O is the centroid. Find the value of x. (Sorry if u cant see the photo :/, but this is Geometry btw)

klemol [59]

Answer: x = 6

==============================================

Explanation:

The medians of a triangle meet up at the centroid in such a way that they cut each other at a ratio of 2:1, meaning that one part of the median is twice as long as the other. In this case, MO is two times longer than OP, so,

OP = 2*MO

and

MP = MO + OP

MP = MO + 2*MO .... replace OP with 2*MO

MP = 3*MO

9x-24 = 3*(x+4) ... plug in the given expressions

9x-24 = 3x+12

9x-3x = 12+24

6x = 36

x = 36/6

x = 6

8 0

3 years ago