1a) A = 4πpw
/4πw = /4πw
A / 4πw = p
1b) A = 4πpw
22 = 4πp(2)
p = 11/4π (≈0.87)
2a) P = 2πr + 2x
P - 2x = 2πr
/2π /2π
P-2x / 2π = r
2b) P = 2πr + 2x
440 = 2πr + 2(110)
r = 110/π (≈35.014)
By definition, the volume of the cone is given by:
V = (1/3) (π) (r ^ 2) (h)
Substituting values we have:
V = (1/3) (π) ((4/2) ^ 2) (5)
V = (20/3) (π)
Then, the volume of the cylinder is:
Vc = 3 * V
Vc = 3 * (20/3) (π)
Vc = 20π
Answer:
the volume of the original cylinder jesse bought is:
Vc = 20π
Hey there! I am on the same one. :) I will help you out a little.
<span>Assume that all six outcomes of a six-sided number cube have the same probability. What is the theoretical probability of each roll?
• 1: 1/6
• 2: 2/6
• 3: 3/6
• 4: 4/6
• 5: 5/6
• 6: 6/6
</span>
<span>Using the uniform probability model you developed, what is the probability of rolling an even number?
1/6 Roll a number cube 25 times. Record your results here.
</span><span>
<span><span>
<span>
<span>1st
toss=</span>6</span>
</span>
<span>
<span>
<span>2nd
toss=</span>4</span>
</span>
<span>
<span>
<span>3rd
toss=</span>6</span>
</span>
<span>
<span>
<span>4th
toss=</span>6</span>
</span>
<span>
<span>
<span>5th
toss=</span>3</span>
</span>
<span>
<span>
<span>6th
toss=</span>3</span>
</span>
<span>
<span>
<span>7th
toss=</span>4</span>
</span>
<span>
<span>
<span>8th
toss=</span>2</span>
</span>
<span>
<span>
<span>9th
toss=</span>6</span>
</span>
<span>
<span>
<span>10th
toss=</span>5</span>
</span>
<span>
<span>
<span>11th
toss=</span>1</span>
</span>
<span>
<span>
<span>12th
toss=</span>4</span>
</span>
<span>
<span>
<span>13th
toss = </span>5</span>
</span>
<span>
<span>
<span>14th
toss =</span>1</span>
</span>
<span>
<span>
<span>15th
toss=</span>4</span>
</span>
<span>
<span>
<span>16th
toss=</span>2</span>
</span>
<span>
<span>
<span>17th
toss=</span>2</span>
</span>
<span>
<span>
<span>18th
toss=</span>2</span>
</span>
<span>
<span>
<span>19th
toss=</span>6</span>
</span>
<span>
<span>
<span>20th
toss=</span>5</span>
</span>
<span>
<span>
<span>21st
toss=</span>3</span>
</span>
<span>
<span>
<span>22nd
toss=</span>4</span>
</span>
<span>
<span>
<span>23rd
toss=</span>3</span>
</span>
<span>
<span>
<span>24th
toss=</span>3</span>
</span>
<span>
<span>
25
toss=5
How
many results of 1 did you have? __2____________ How
many results of 2 did you have? ____4__________ How
many results of 3 did you have? ____5__________ How
many results of 4 did you have? ______5________ How
many results of 5 did you have? ______4________
How
many results of 6 did you have? ______5________
Based
on your data, what is the experimental probability of each roll?
<span>
1. 2/25 or 0.08
2. 4/25 or 0.16
3. 5/25 or 0.24
4. 5/25 or 0.2
5.4/25 or 0.16
<span>
6. 5/25 or 0.2</span></span>Using
the probability model based on observed frequencies, what is the probability of
rolling an even number?
3/6 = ½ or 0.5
Was your experimental probability
different than your theoretical probability? Why or why not?
<span>It somewhat is! The
denominator is 25 for the experimental probability, and 6 for the theoretical
probability.</span><span>
</span><span>Have a lovely day! Cheerio. :) </span></span>
</span>
</span></span>
