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3 years ago

PLEASE HELP!

Mathematics

2 answers:

yuradex [85]3 years ago

5 0

Answer:

Options B and D

Step-by-step explanation:

Phrase shift of a trignometric function is the horizontal shift of the function towards right or left.

Vertical shift is shift up or down.

The graph of y = sin x is translated three units down.

-- This is vertical shift and not phase shift.

The graph of y = csc x is translated three units to the right

-- This is a phase shift as y = csc (x+3)

The graph of y = cos x is translated three units up. -- No, vertical shift.

The graph of y = sec x is translated three units to the left. -- Yes, phase shift

The graph of y = cot x is reflected over the horizontal axis. -- No, reflection

The graph of y = tan x is reflected over the vertical axis.-- No, reflection

Only options B D are phase shifts.

Anettt [7]3 years ago

4 0

Answer: 2,3 and 4

Step-by-step explanation:

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Each score in a set of data is multiplied by 3, and then 4 is subtracted from the result. If the original mean is 10 and the ori

olganol [36]

The new mean and standard deviation is 26 and 15, when each score in data set is multiplied by 5 and then 7 is added.

According to the question,

Original mean is 10 and original standard deviation is 5 . In order to find to new mean and standard deviation when each score in data set is multiplied by 5 and then 7 is added.

First "change of scale" when every score in a data set is multiplied by a constant, its mean and standard deviation is multiplied by a same constant.

Mean: 10*3 = 30

Standard deviation: 5*3 = 15

Secondly "change of origin" when every score in a data set by a constant, its mean get added or subtracted by the same constant and standard deviation remains constant.

Applying change of origin in the above mean and standard deviation

Mean: 30 - 4 = 26

Standard deviation: Remains same = 15

Hence, the new mean and standard deviation is 26 and 15, when each score in data set is multiplied by 5 and then 7 is added.

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2 years ago

4)) What is the volume? 19 yd 12 yd 12 yd

Zepler [3.9K]

Answer:

2,736

Step-by-step explanation:

7 0

3 years ago

Shelia's measured glucose level one hour after a sugary drink varies according to the normal distribution with μ = 117 mg/dl and

TiliK225 [7]

Answer:

The level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L is L = 127.1 mg/dl.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$