Answer:
Step-by-step explanation:
The length of a photograph is 3cm less than twice the width. The area is 54cm². Find the dimentions of the photograph.
2 answers:
L=2w-3
w(2w-3)=54
2w²- 3w-54=0
A= 2 , B= -3, C= -54
sub values into quadratic formula
i attached picture of formula
Final answer: you will be given 2 answers 6 and -4.5. -4.5 is rejected since a negative value cannot represent length because that just doesn't make sense.
w=6
Check:
L=2w-3
=2(6)-3
=12-3
=9
9*6=54
Therefore the dimensions of the photograph are 6 cm by 9 cm
w(2w-3)=54
2w²- 3w-54=0
A= 2 , B= -3, C= -54
sub values into quadratic formula
i attached picture of formula
Final answer: you will be given 2 answers 6 and -4.5. -4.5 is rejected since a negative value cannot represent length because that just doesn't make sense.
w=6
Check:
L=2w-3
=2(6)-3
=12-3
=9
9*6=54
Therefore the dimensions of the photograph are 6 cm by 9 cm
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Step-by-step explanation:
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Then:
Answer:
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Step-by-step explanation:
-5c + 2 < 27
- 2 - 2 Subtract 2 from both sides
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I graphed the inequality on the graph below.
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