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mrs_skeptik [129]

3 years ago

8

Square root of 100/121

1 answer:

klasskru [66]3 years ago

7 0

Ah... good ol' square roots...

Whenever you take the square root of multiplication or division, you can do the square roots separately. So, we can write:

$\sqrt{\frac{100}{121}} = \frac{\sqrt{100}}{\sqrt{121}}$

This nifty truth allows us to easily find the answer:
$\frac{\sqrt{100}}{\sqrt{121}} = \frac{10}{11}$

All done!

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Answer:

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Is the equations of quadratic number pattern will always have real roots

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3 years ago

Sarah’s stands on a ground and sights the top of a steep Clift at a 60 degree angle of elevation she then steps back 50 meters t

SashulF [63]

Answer:

Cliff is 45 m tall.

Step-by-step explanation:

Given:

Height of Sarah = 1.8 m

Angle of elevation = 60°

Angle of elevation 50 m back = 30°

As shown in the figure we have two right angled triangles SPQ and SPR.

Let the height of the cliff be $h$ meters and $h= h_1+h_s$ .

Using trigonometric ratios:

tan (Ф) = opposite/adjacent

In ΔSPQ. In ΔSPR.

⇒ $tan(60) = \frac{h_1}{x}$ ...equation (i) ⇒ $tan (30)=\frac{h_1}{x+50}$ ...equation (ii)

Dividing equation (i) and (ii)

⇒ $\frac{tan(60)}{tan(30)} = \frac{h_1}{x} \times \frac{x+50}{h_1}$

⇒ $3 = \frac{x+50}{x}$

⇒ $3x=x+50$

⇒ $3x-x=50$

⇒ $2x=50$

⇒ $x=\frac{50}{2}$

⇒ $x=25$ meters

To find $h_1$ plugging $x=25$ in equation (i)

⇒ $h_1=x\times tan(60)$

⇒ $h_1=25\times 1.73$

⇒ $h_1=43.25$ meters

The height of the cliff from ground :

⇒ $h= h_1+h_s$

⇒ $h= 43.25+1.8$

⇒ $h=45.05$ meters

The cliff is 45 m tall to the nearest meter.

8 0

4 years ago

How many acres are there in the W 1/2 of the S 1/2 of the SW 1/2 of a section of land? 50 acres? 15 acres? 80 acres? 160 acres?

tamaranim1 [39]

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There are 640 acres in a section, so 1/8 section = 80 acres.

_____

In surveying terms, "SW 1/2 of a section" is not a realistic specification of a piece of property.

5 0

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