Answer:
Option C.
Step-by-step explanation:
The given expression is
It can be rewritten as
According to De moivre's Theorem:
Using De moivre's Theorem, we get
Therefore, the correct option is C.
![f(x)=(1-x^2)^{\frac{2}{3}}\implies \cfrac{df}{dx}=\cfrac{2}{3}(1-x^2)^{-\frac{1}{3}}\implies \cfrac{df}{dx}=\cfrac{2}{3\sqrt[3]{1-x^2}}](https://tex.z-dn.net/?f=f%28x%29%3D%281-x%5E2%29%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7Bdf%7D%7Bdx%7D%3D%5Ccfrac%7B2%7D%7B3%7D%281-x%5E2%29%5E%7B-%5Cfrac%7B1%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7Bdf%7D%7Bdx%7D%3D%5Ccfrac%7B2%7D%7B3%5Csqrt%5B3%5D%7B1-x%5E2%7D%7D)
when it comes to a rational expression, we can get critical points from, zeroing the derivative "and" from zeroing the denominator alone, however the denominator provides critical valid points that are either "asymptotic" or "cuspics", namely that the function is not differentiable or not a "smooth line" at such spot.
if we get the critical points from the denominator on this one, we get x = ±1, both of which are cuspics. Check the picture below.
(-18/2, -13)- Tip: draw a line and label it with the coordinates. Then just add/ subtract to get your answer
Answer:
C. 62
Step-by-step explanation:
ADC is 90 degrees. 90 - 28 = 62
2y + 2x = 6
2y - x = 12
Subtract
3x = -6, x = -2
2(-2) + 2y = 6
-4 + 2y = 6
2y = 10, y = 5
Final solution: x = -2, y = 5