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Levart [38]
3 years ago
13

Please help me asap

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
6 0

The equation of a line is y = mx + b  [m is the slope, b is the y-intercept or the y value when x = 0  ---->  (0, y) or the point where the line goes through the y-axis]

To find the slope, you use the slope formula (m):

m=\frac{y_2-y_1}{x_2-x_1}           and plug in 2 points

I will use the points (0, 0) and (1, 8)

(0, 0)  ---->  (x₁, y₁)

(1, 8) ---->   (x₂, y₂)

m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{8-0}{1-0}

m = 8

Since you know m, plug it into the equation.

y = 8x + b

The graph shows that the y-intercept is 0, so plug it into the equation

y = 8x    

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What are the intercepts of 2x + 3y – 6z = 30?
ycow [4]

Intercept of equation 2x + 3y - 6z = 30 is (15, 0, 0) , (0, 10, 0) and (0, 0, -5)

<h3><u>Solution:</u></h3>

Given equation is:

2x + 3y - 6z = 30

We have to find the intercepts

Intercept are the point where equations cut the x- axis, y- axis and z- axis.

<em><u>Thus, at x- axis :</u></em>

y and z both are zero

So substitute y = 0 and z = 0 in given equation

2x + 3(0) - 6(0) = 30

2x = 30

x = 15

<h3>Thus the intercept is (15, 0, 0)</h3>

<em><u>Thus at y - axis:</u></em>

x and z both are zero

So substitute x = 0 and z = 0 in given equation

2(0) + 3y -6(0) = 30

0 + 3y + 0 = 30

3y = 30

y = 10

<h3>Thus the intercept is (0, 10, 0)</h3>

<em><u>Thus at z - axis:</u></em>

x and y are both zero

So substitute x = 0 and y = 0 in given equation

2(0) + 3(0) - 6z = 30

-6z = 30

z = -5

<h3>Thus the intercept is (0, 0, -5)</h3>

Thus, intercept of equation 2x + 3y - 6z = 30 is (15,0,0) ,(0,10,0) and (0,0,-5)

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