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Levart [38]
3 years ago
13

Please help me asap

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
6 0

The equation of a line is y = mx + b  [m is the slope, b is the y-intercept or the y value when x = 0  ---->  (0, y) or the point where the line goes through the y-axis]

To find the slope, you use the slope formula (m):

m=\frac{y_2-y_1}{x_2-x_1}           and plug in 2 points

I will use the points (0, 0) and (1, 8)

(0, 0)  ---->  (x₁, y₁)

(1, 8) ---->   (x₂, y₂)

m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{8-0}{1-0}

m = 8

Since you know m, plug it into the equation.

y = 8x + b

The graph shows that the y-intercept is 0, so plug it into the equation

y = 8x    

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(2x105)/(3x103) + 3x103 * 5x102
AleksAgata [21]

Answer:

1500066.66

Step-by-step explanation:

Given: (2\times10^{5} )/(3\times 10^{3} ) + 3\times10^{3} \times 5\times10^{2}

Now, simplifying it.

Using PEDMAS in solving the expression

First opening the parenthesis

= 2\times10^{5} /3\times 10^{3}  + 3\times10^{3} \times 5\times10^{2}

Next dividing the number

as per law of indices, x^{m} \div x^{n} = x^{m-n}

= 2\times10^{5-3} /3 + 3\times10^{3} \times 5\times10^{2}

= 2\times10^{2} /3 + 3\times10^{3} \times 5\times10^{2}

= \frac{2\times10^{2} }{3}  + 3\times10^{3}  \times 5\times10^{2}

Next multiplying the number as per PEDMAS

as per law of indices, x^{m} \times x^{n} = x^{m+n}

= \frac{2\times10^{2} }{3}  + 15\times10^{3+2}

= \frac{2\times10^{2} }{3}  + 15\times10^{5}

= \frac{2\times 100}{3}  + 15\times10^{5}

Next dividing the number as per PEDMAS

= 2\times 33.33  + 15\times10^{5}

Next multiplying the number as per PEDMAS

= 66.66+1500000

Now adding the number

= 1500066.66

4 0
3 years ago
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valentina_108 [34]

Answer:

The answer is 48in

Step-by-step explanation:

7 0
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Mekhanik [1.2K]

Answer:

The base is 8 and the height is 3, so the area is 8 (3) = 24 square units.

Step-by-step explanation:

The area of the parallelogram is given by the following expression:

A = \|\vec u\times \vec v\|

The vectors are, respectively:

\vec u = (10-2, 1 - 1,0-0)

\vec u = (8,0,0)

The base of the parallelogram is 8 units.

\vec v = (8-2, 4-1,0-0)

\vec v = (6,3,0)

The height of the parallelogram is 3 units.

The cross product of both vectors is:

\vec u \times \vec v = (0,0,24)

The area of the parallelogram is given by the norm of the resulting vector:

\|\vec u \times \vec v\| = 24

8 0
3 years ago
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(x+3)(x+12)

Step-by-step explanation:

you need numbers that

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(125/3 = 41.6..., 41.6... rounded is 42)
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