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Levart [38]
3 years ago
13

Please help me asap

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
6 0

The equation of a line is y = mx + b  [m is the slope, b is the y-intercept or the y value when x = 0  ---->  (0, y) or the point where the line goes through the y-axis]

To find the slope, you use the slope formula (m):

m=\frac{y_2-y_1}{x_2-x_1}           and plug in 2 points

I will use the points (0, 0) and (1, 8)

(0, 0)  ---->  (x₁, y₁)

(1, 8) ---->   (x₂, y₂)

m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{8-0}{1-0}

m = 8

Since you know m, plug it into the equation.

y = 8x + b

The graph shows that the y-intercept is 0, so plug it into the equation

y = 8x    

You might be interested in
Find the area of rectangle ABCD
satela [25.4K]

9514 1404 393

Answer:

  D. 12

Step-by-step explanation:

There are a number of ways to find the area of this rectangle. Perhaps the most straightforward is to find the lengths of the sides and multiply those. The distance formula is useful.

  d = √((x2 -x1)^2 +(y2 -y1)^2)

Using the two upper-left points, we find the length of that side to be ...

  d = √((3 -0)^2 +(3 -0)^2) = √(9 +9) = √18 = 3√2

Similarly, the length of the lower-left side is ...

  d = √((-2 -0)^2 +(-2 -0)^2) = √(4+4) = √8 = 2√2

Then the area of the rectangle is ...

  A = LW

  A = (3√2)(2√2) = 3·2·(√2)^2 = 3·2·2 = 12

The area of rectangle ABCD is 12.

_____

Other methods include subtracting the area of the corner triangles from the area of the bounding square:

  5^2 -2(1/2)(3·3) -2(1/2)(2·2) = 25 -9 -4 = 12

4 0
3 years ago
Help please!!
andrey2020 [161]
1^-10 if I’m wrong let me kno
5 0
3 years ago
Help!<br> It's a picutre
9966 [12]

Here is your answer

a) 5x-2y= 1

REASON:

6-2(x-y)=3x+5

6-2x+2y= 3x+5

3x+2x-2y= 6-5

5x-2y= 1

HOPE IT IS USEFUL

3 0
3 years ago
WILL GIVE BRAINLIEST.
Elena L [17]

Answer:

\tan(\theta) = undefined

Step-by-step explanation:

Given

\sin(\theta) = -1

Required

Determine \tan(\theta)

We know that:

\sin^2(\theta) + \cos^2(\theta) = 1

This gives:

(-1)^2 + \cos^2(\theta) = 1

1 + \cos^2(\theta) = 1

Collect like terms

\cos^2(\theta) = 1 -1

\cos^2(\theta) = 0

Take square roots

\cos(\theta) = \sqrt 0

\cos(\theta) = 0

By tan identity

\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}

\tan(\theta) = \frac{-1}{0}

\tan(\theta) = undefined

6 0
3 years ago
For each inequality draw a number line and show all points that satisfy it.
disa [49]

0o----------------------------o5

Step-by-step explanation:

7 0
3 years ago
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