Question

Find the coordinates of the point

Answer 1

Answer:

$(x,y) = (\frac{-10}{13},3)$

Step-by-step explanation:

Question is not well formatted; However, the given parameters are

Given

Point = 3/10

A = (-4,-6)

B = (10,7)

Required

Determine the coordinates of the point

Represent the point as ratio

$Point = 3:10$

The coordinates can be solved using

$(x,y) = (\frac{mx_2 + nx_1}{m+n},\frac{my_2 + ny_1}{m+n})$

Where

$m:n = 3:10$

$(x_1,y_1) = (-4,-6)$

$(x_2,y_2) = (10,7)$

Substitute these values in the above formula:

$(x,y) = (\frac{mx_2 + nx_1}{m+n},\frac{my_2 + ny_1}{m+n})$

$(x,y) = (\frac{3 * 10 + 10 * -4}{3+10},\frac{3 * 7 + 10 * -6}{10+3})$

$(x,y) = (\frac{30 -40}{13},\frac{21 -60}{13})$

$(x,y) = (\frac{-10}{13},\frac{-39}{13})$

$(x,y) = (\frac{-10}{13},3)$

Hence;

The coordinates of the point is $(x,y) = (\frac{-10}{13},3)$