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4 years ago

14

Marin writes the functions m(x) = StartFraction 3 x Over x + 7 EndFraction and n(x) = StartFraction 7 x Over 3 minus x EndFracti

on. Which equation must be true for m(x) and n(x) to be inverse functions?

1 answer:

cricket20 [7]4 years ago

5 0

Answer: B

Step-by-step explanation:

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Item has been reduced by 80% what is the price of the item now?

Eva8 [605]

I think you use

xamount(1-.8)

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1 being 100%

so .2 or 20% remaining multiplied by whatever amount.

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4 years ago

What decimal is being represented by the decimal grid?

denis-greek [22]

Answer:

232

Step-by-step explanation:

232, because each has 100 squares so if you add the 2 filled squares you will get 200. Then if you count the last one only 32 is filled, when u add it it gives you 232

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2 years ago

(sinA-cosA+1)/(sinA+cosA-1)=2(1+cosecA)

borishaifa [10]

Answer:

The trigonometrical expression is sin² A + sin A - 2 cos A - 2 cos A × sin A = 0

Step-by-step explanation:

Given Trigonometrical function as :

$\frac{sin A - cos A + 1}{sin A + cos A - 1}$ = 2 (1 + cosec A)

Or, $\frac{sin A + ( 1 - cos A)}{sin A - (1 - cos A)}$ = 2 (1 + cosec A)

,<u> Now, rationalizing </u>

$\frac{(sin A + ( 1 - cos A)) \times (sin A + (1 - cosA))}{(sin A - (1 - cos A))\times (sin A + (1 - cos A))}$ = 2 (1 + cosec A)

Or, $\frac{(sin A + (1 - cos A))^{2}}{sin^{2} - (1-cos A)^{2}}$ = 2 ( 1 + $\dfrac{1}{\textrm sinA}$

Or, $\frac{sin^{2}A + (1 - cosA)^{2} + 2 \times sin A \times (1 - cos A)}{sin^{2}A - (1 + cos^{2}A - 2 cos A)}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{sin^{2}A + 1 + cos^{2}A - 2 cos A + 2 sin A - 2 sin A cos A}{sin^{2}A - 1 - cos^{2}A +2 cos A}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{sin^{2}A + 1 + cos^{2}A - 2 cos A + 2 sin A - 2 sin A cos A}{sin^{2}A - (sin^{2}A + cos^{2}A) - cos^{2}A +2 cos A}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{2- 2 cos A + 2 sin A - 2 sin A cos A}{- 2cos^{2}A +2 cos A}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{1- cos A + sin A - sin A cos A}{- cos^{2}A + cos A}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{(1- cos A) + sin A (1-cos A)}{cos A(1 - cos A)}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{(1- cos A) (1 + sinA)}{cos A(1 - cos A)}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{(1 + sinA)}{(cos A)}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, sin A + sin² A = 2 cos A (1 + sin A)

Or, sin A + sin² A = 2 cos A + 2 cos A × sin A

Or, sin² A + sin A - 2 cos A - 2 cos A × sin A = 0

So,The trigonometrical expression is sin² A + sin A - 2 cos A - 2 cos A × sin A = 0 Answer

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3 years ago

What is the volume of this square pyramid?<br> Enter your answer in the box.<br><br> cm³

Alenkinab [10]

The problem can be solve using the formula for the volume of square pyramid such as below:
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From the picture, we are given with values such as:
a = 14 cm
h= 24 cm

Solving for the volume, we have:
Volume = 14²*(24/3)
Volume = 1568 cm³

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3 years ago

What is the slope of the line in the graph?

BabaBlast [244]

For every one unit to the right we go up one unit, i.e. rise/run = 1/1 = 1. That's a textbook slope of 1.

Answer: 1

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4 years ago

Read 2 more answers