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Troyanec [42]
3 years ago
6

-4.7 divided by 1\4 ????????????????

Mathematics
2 answers:
tatiyna3 years ago
4 0

Answer:

-18.8

Step-by-step explanation:

:)

Nady [450]3 years ago
3 0

Answer:

-18.8

Step-by-step explanation:

1/4 as a decimal is 0.25 so then if you divide -4.7 by 0.25 the answer is -18.8 :)

I hope this helped :)

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The question is below:
SSSSS [86.1K]

Answer:

Triangles ABE and CDE are congruent by AAS.

Step-by-step explanation:

AB ≅ DC   (Opposite sides of a parallelogram are congruent.

m < AEB = m < DEC     (Vertical angles).

m < ABE = m < EDC     ( Alternate Interior angles).

So triangles  ABE and CDE are congruent by AAS.

5 0
3 years ago
Negative 5 (2 1/6) equals.
mr Goodwill [35]

Answer: -65/6

Step-by-step explanation:

7 0
2 years ago
Janice NEEDS 3 GALLONS of lemonade for a party. She has 4 quarts, 6 pints and 4 cups of lemonade already made. How many CUPS of
slamgirl [31]

Answer:

32 cups

Step-by-step explanation:

To find the total number of cups, we have to convert the measures that are not in cups to cups and add

1 quart  = 4 cups

4 quarts = 4 x4 = 16 cups

1 pint = 2 cups

6 pints = 2 x 6 = 12 pints

total number of cups = 16 + 12 + 4 = 32 cups

4 0
3 years ago
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LUCKY_DIMON [66]

Answer:

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3 0
3 years ago
Which of the following is equivalent to tan2θcos(2θ) for all values of θ for which tan2θcos(2θ) is defined?
Aloiza [94]

Answer:

2sin²θ - tan²θ

Step-by-step explanation:

Given

tan²θcos(2θ)

Required

Simplify

We start by simplifying cos(2θ)

cos(2θ) = cos(θ+θ)

From Cosine formula

cos(A+A) = cosAcosA - sinAsinA

cos(A+A) = cos²A - sin²A

By comparison

cos(2θ) = cos(θ+θ)

cos(2θ) = cos²θ - sin²θ ----- equation 1

Recall that cos²θ + sin²θ = 1

Make sin²θ the subject of formula

sin²θ = 1 - cos²θ

Substitute sin²θ = 1 - cos²θ in equation 1

cos(2θ) = cos²θ - (1 - cos²θ)

cos(2θ) = cos²θ - 1 +cos²θ

cos(2θ) = cos²θ + cos²θ - 1

cos(2θ) = 2cos²θ - 1

Substitute 2cos²θ - 1 for cos(2θ) in the given question

tan²θcos(2θ) becomes

tan²θ(2cos²θ - 1)

Open brackets

2cos²θtan²θ - tan²θ

------------------------

Simplify tan²θ

tan²θ = (tanθ)²

Recall that tanθ =  sinθ/cosθ

So, we have

tan²θ = (sinθ/cosθ)²

tan²θ = sin²θ/cos²θ

------------------------

Substitute sin²θ/cos²θ for tan²θ

2cos²θtan²θ - tan²θ becomes

2cos²θ(sin²θ/cos²θ) - tan²θ

Open bracket (cos²θ will cancel out cos²θ) to give

2(sin²θ) - tan²θ

2sin²θ - tan²θ

Hence, the simplification of tan²θcos(2θ) is 2sin²θ - tan²θ

Option E is correct

7 0
3 years ago
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