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ra1l [238]
3 years ago
6

What is the correct classification for each given angle?

Mathematics
2 answers:
LuckyWell [14K]3 years ago
8 0

Answer:

Angle RQU is obtuse, since 19°+71°+18°=108° and 108° > 90°

Angle SQU is acute, since 71°+18°=89° and 89° < 90°

Angle RQT is a right angle, since 19°+71°=90°

None of the angles are straight angles, as they are not equal to 180°.

Katena32 [7]3 years ago
3 0

Answer:

\angle RQU=108^{\circ}-Obtuse angle

\angle SQU=89^{\circ}-acute angle

[tex]\angle RQT=90^{\circ}- Right angle

Step-by-step explanation:

We are given that

\angle RQS=19^{\circ}{/tex][tex]\angle SQT=71^{\circ}

\angle TQU=18^{\circ}

We have to find angle RQU ,angle SQU and angle RQT and match with correct classification of angles.

\angle RQU=\angle RQS+\angle SQT+\angle TQU=19+71+18=108^{\circ}

The measurement of angle RQU is greater than 90 degrees.Therefore, it is an obtuse angle.

\angle SQU=\angle SQT+\angle TQU=71+18=89^{\circ}

The measure of angle SQU is less than 90 degrees.Therefore, it is an acute angle.

\angle RQT=\angle RQS+angle SQT=19+71=90^{\circ}

The measure of angle RQT is equal to 90 degrees .Therefore, it is right angle.

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Answer:

Step-by-step explanation:

\int\limits^2_0 {(x^2-4x)} \, dx       n=8     f(x) = x² - 4x

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Reiman sum is

R_8=\delta x[f(x_1)+f(x_2)+...f(8)]\\\\0.25[f(0.25)+f(0.5)+...+f(2)]\\\\0.25\times[-23.25]\\=-5.8125

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