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san4es73 [151]
3 years ago
15

What is the volume of the cone?

Mathematics
1 answer:
jonny [76]3 years ago
7 0

The area of a cone in terms of the area of the base and the height is as follows:

A = \dfrac{1}{3} B h

  • B is the area of the base
  • h is the height of the cone

Thus, we can solve the problem. We are trying to find the area of the base and are given the other values we need to solve the problem. Thus, let's substitute and find our solution.

124 = \dfrac{1}{3} B (12) = 4B

B = 31


The solution to the problem is 31.

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The table displays the frequency of scores for a calculus class on an exam. The mean of the exam scores is 3.5. Score 1 2 3 4 5
vladimir1956 [14]

Answer:

f=11

Mode=4

Median=4

Explanation:

We are given that

a.Mean of the exam score,\bar x=3.5

Score(x)   frequency   C.F

1                  1                 1

2                  3                4

3                  f                 15(4+f=4+11)

4                  13               28

5                   4               32

\sum f_i=1+3+f+13+4=21+f

\sum f_ix_i=1(1)+2(3)+3(f)+4(13)+5(4)=1+6+3f+52+20=79+3f

(\bar x)=\frac{\sum f_ix_i}{\sum f_i}

Using the formula

3.5=\frac{79+3f}{21+f}

73.5+3.5f=79+3f

3.5f-3f=79-73.5

0.5f=5.5

f=\frac{5.5}{0.5}=11

b.Mode:The number which is repeat most times .

4 repeat most times

Hence, mode of all exam scores=4

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Median=\frac{(\frac{n}{2})^{th}+(\frac{n}{2}+1)^{th}}{2}

Median=\frac{16th+17th}{2}=\frac{4+4}{2}=\frac{8}{2}=4

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