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san4es73 [151]
3 years ago
15

What is the volume of the cone?

Mathematics
1 answer:
jonny [76]3 years ago
7 0

The area of a cone in terms of the area of the base and the height is as follows:

A = \dfrac{1}{3} B h

  • B is the area of the base
  • h is the height of the cone

Thus, we can solve the problem. We are trying to find the area of the base and are given the other values we need to solve the problem. Thus, let's substitute and find our solution.

124 = \dfrac{1}{3} B (12) = 4B

B = 31


The solution to the problem is 31.

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{20, 68, 70, 70, 71, 72, 75, 76}
guapka [62]

Answer:

Mean: 65.25

Median: 70.5

Mode: 70

Step-by-step explanation:

Mean is the sum of the set of numbers divided by the number of numbers in the set.

20+68+70+70+71+72+75+76=522

522/8=65.25

The median is the number that is in the middle of the set when put in numerical order.

Since there is an even amount of numbers, the two middle numbers are 70 and 71, so you would take the mean of these two numbers to find the median.

70+71=141

141/2=70.5

The mode is the number that occurs most frequently in the set.

70 appears more times than any other number, therefore it is the mode.

5 0
4 years ago
Read 2 more answers
WHAt is the equation of the graph below?
VARVARA [1.3K]
I’m pretty sure the answer is (y=sin(3x))
.
.
.
You can use desmos for these kinds of questions(desmos is a graphing app)
6 0
4 years ago
Shenhed finished his math assament in 3/8
Elenna [48]
Math assignment = 3/8 hours
History assignment = 1/4 hours

We can not compare this as both fractions do not have alike denominators.

We can fix this problem easily by turning 3/8 and 1/4 into alike denominator fractions.

We can turn 1/4 into 2/8 as it is equivalent fractions.

1 x 2 = 2
4 x 2 = 8

(Whatever you do to the denominator, you have to do the same to the numerator)

Once we get this, we can see that Shen spent 2/8 hours on his homework while he spent 3/8 hours on his math assignment.

3/8 - 2/8 = 1/8

1/8 = 0.125

Shen spent 1/8 of an hour (or 0.125 of an hour) more on his math assignment than his history assignment.
4 0
2 years ago
You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta
vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }

m = -\frac{\cos 2\theta}{\sin \theta}

The tangent line is horizontal when m = 0. Then:

\cos 2\theta = 0

2\theta = \cos^{-1}0

\theta = \frac{1}{2}\cdot \cos^{-1} 0

\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right), for all i \in \mathbb{N}_{O}

\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}, for all i \in \mathbb{N}_{O}

The first four solutions are:

x:   \sqrt{2}   -\sqrt{2}  -\sqrt{2}  \sqrt{2}

y:     1        -1        1     -1

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

6 0
3 years ago
How do I become a better math student
loris [4]

Answer:

by continueing to study

Step-by-step explanation:

8 0
3 years ago
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