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True [87]
4 years ago
13

{20, 68, 70, 70, 71, 72, 75, 76}

Mathematics
2 answers:
Firdavs [7]4 years ago
8 0

Answer:

mean:65.25

median:70.5

mode:70

Step-by-step explanation:

mean: add up all numbers which will give u 522 then u divide the amount of numbers which is 8 then you'll get 65.25.

median: u would find the middle number by putting all numbers into ascending order and work into the middle by crossing off numbers at each end. which will leave u with 2 numbers 70,71 so u add them and get 141 then divide by 2 which is 70.5.

Mode: find the most common number which is 70

guapka [62]4 years ago
5 0

Answer:

Mean: 65.25

Median: 70.5

Mode: 70

Step-by-step explanation:

Mean is the sum of the set of numbers divided by the number of numbers in the set.

20+68+70+70+71+72+75+76=522

522/8=65.25

The median is the number that is in the middle of the set when put in numerical order.

Since there is an even amount of numbers, the two middle numbers are 70 and 71, so you would take the mean of these two numbers to find the median.

70+71=141

141/2=70.5

The mode is the number that occurs most frequently in the set.

70 appears more times than any other number, therefore it is the mode.

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5 ft

Step-by-step explanation:

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7 0
3 years ago
An elementary school is in a growing suburb. The school’s principal estimates that the current enrollment of 750 students will i
HACTEHA [7]

Answer:

62.9% in ten years

Step-by-step explanation:

This type of growth corresponds to what is called an exponential growth, since in the expression for the number of students keep including the multiplication of the same factor as the years go by, Let's start by analyzing what happens the first year:

The initial enrollment of 750 is expected to grow by 5%, therefore after one year the enrollment should be:

After one year = Year_1 = 750 + 5% increase = 750+750*0.05=750(1+0.05)

where we have used the decimal form of 5% as he factor 0.05 multiplying 750 (the initial enrollment) to give the increase.

After the second year, we consider a starting value of Year_1 enrollments that will increase another 5%, which gives: Year_2 = Year_1 + Year_1 * 0.05= Year_1 (1 + 0.05).

So replacing Year_1 by its original expression (750(1+0.05)) we notice that Year_2 = 750 * (1+0.05) * (1+0.05) = 750 * (1+0.05)^2

We can go on with this same reasoning and find that each year includes a new factor (1+0.05) to the new increasing enrollment.

At the end of 10 years, the number of enrollment will be:

750*(1+0.05)^10=1221.67

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This means and increase of: \frac{1222-750}{750} =0.62933

That is approximately 62.9%

6 0
3 years ago
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