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aalyn [17]
3 years ago
10

How many solutions does the equation −4y + 4y + 2 = 2 have? Two None One Infinitely many

Mathematics
1 answer:
Ulleksa [173]3 years ago
5 0

Answer:

Infinitely many

Step-by-step explanation:

Because the equation is equal to 0+0

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Solve s=2(lw+lh+wh) for w
Scilla [17]

                                                                   s = 2(lw + lh + wh)

Divide each side by  2 :                            s/2 = lw + lh + wh

Subtract 'lh' from each side:                s/2 - lh = lw + wh

Combine the 'w' terms:                        s/2 - lh = w(l + h)

Divide each side by (l + h):  (s/2 - lh) / (l + h) = w

7 0
3 years ago
A triangle with three 60° angles is always a/an _______________ triangle.
ki77a [65]
It’s called an equilateral triangle because all sides are even. A triangle equals 180 degrees. So, 60 degrees x 3 sides = 180 degrees
7 0
3 years ago
Tell whether each function is linear or nonlinear use the drop down menus to show yo answer
saveliy_v [14]

Answer:

If it's a straight line it's linear, if it curves it's non-linear.

Step-by-step explanation:

6 0
3 years ago
If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

4 0
2 years ago
Help me for 3???????
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