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Ivanshal [37]
3 years ago
7

The local diner offers a meal combination consisting of an appetizer, a soup, a main course, and a dessert. There are three appe

tizers, three soups, three main courses, and three desserts. Your diet restricts you to choosing between a dessert and an appetizer. (You cannot have both.) Given this restriction, how many three-course meals are possible
Mathematics
1 answer:
BigorU [14]3 years ago
5 0

Answer:

There are 2 * 32 = 64 possible ways for choosing three course meal.

Step-by-step explanation:

1-If we choose an appetizer, main course and a soup then there are 32 ways to choose this three course meal. 4 * 2 * 4 = 32 ways. There will be an appetizer, main course and a soup in the meal.

2-If we choose a soup, main course and a dessert then there are 32 ways to choose this three course meal. 4 * 2 * 4 = 32 ways. There will be a soup, main course and a dessert in the meal.

There are 2 possible ways to choose either an appetizer or dessert in a 3 course meal. There will be 64 ways in total for the three course meal.

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If the Probability of an event happening is 70%, what are the ODDS of the event happening? Group of answer choices 7:10 7:3 10:7
Vladimir [108]

Answer:

The odds of the event happening = 7:3

Step-by-step explanation:

Given

Probability of an event happening = 70%

To find the odds of the event happening.

Solution:

Odds of an event happening is the ratio of the probability of the event happening and the probability of the event not happening.

Probability of the event not happening will be = 100\%-70\%=30\%

So, the ratio of the probabilities of event happening and not happening can be given as:

⇒ \frac{70\%}{30\%}

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⇒  \frac{70}{100}\times \frac{100}{30} [Replacing division sign with multiplication sign by taking reciprocal of divisor.]

⇒ \frac{70}{30}  [Canceling out the common terms]

⇒ \frac{7}{3}  [Reducing fraction to simplest form]

Thus, odds of the event happening is = 7:3

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