Answer:
A' = (0,0)
B'=(8,0)
C'=(8,2)
D'=(0,2)
It is not a rigid motion.
Step-by-step explanation:
To use the mapping rule, substitute the original x and y values in it.
The coordinates of A are (0,0).
Using the mapping rule, the x coordinate of A' = 2x0 = 0
Using the mapping rule, the y coordinate of A' = (1/2)x0=0
So A' will not change locations. The image will be at (0,0).
The coordinates of B are (4,0)
Using the mapping rule, the x-coordinate of B' = 2x4 = 8
Using the mapping rule, the y-coordinate of B' = (1/2)x0=0
Therefore the image of B' will be located at coorindate (8,0)
The coorindates of C are (4,4).
Using the mapping rule, the x-coordinate of C' = 2x4=8
Using the mapping rule, the y-coordinate of C' = (1/2)x4=2
Therefore the image of C' will be located at coordinate (8,2)
The coordinates of D are (0,4)
Using the mapping rule, the x-coordinate of D' = 2x0 = 0
Using the mapping rule, the y-coordinate of D' = (1/2)x4=2
Therefore the image of D' will be located at coordinate (0,2)
<em>Is the transformation a rigid motion?</em>
NO, this transformation is not a rigid motion because the relative distance between the points does not stay the same after they have been transformed. The transformation is not a translation , rotation, reflection, nor glide reflection.
