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Snezhnost [94]
3 years ago
15

(3x^4-x^3-4x^2-2x-20)÷(x^2+2) using long division

Mathematics
1 answer:
rosijanka [135]3 years ago
7 0
Answer is below..............

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The area of a right triangle is given by the expression:
lorasvet [3.4K]

The expression that models the length of the second leg of the triangle is <u>2x - 3.</u>

<u><em>Recall</em></u>:

The area of a triangle = \frac{1}{2} bh

<em><u>Given</u></em>:

Area of triangle = \frac{1}{2} (6x^2 - 7x - 3)

Length of one of the legs = 3x + 1

Therefore, it means that multiplying both legs should give us:

6x^2 - 7x - 3

To find the expression that models the other leg, divide 6x^2 - 7x - 3 by 3x + 1:

  • <em>Thus</em>:

\frac{6x^2 - 7x - 3}{3x - 1}

  • Factorize the numerator

\frac{6x^2 - 2x - 9x - 3}{3x - 1}\\\\\frac{2x(3x - 1) - 3(3x - 1)}{3x - 1}\\\\\frac{(2x- 3)(3x - 1)}{3x - 1}

  • Simplify

\frac{(2x- 3)(3x - 1)}{3x - 1} = 2x- 3

Therefore, the expression that models the length of the second leg of the triangle is <u>2x - 3.</u>

<u></u>

<u></u>

Learn more here:

brainly.com/question/20712284

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If you combine these you will get 6x^2 [8+(-2)=6]

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3 years ago
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