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lawyer [7]
3 years ago
5

Whats the common factor of 18,27

Mathematics
1 answer:
Leviafan [203]3 years ago
5 0

Well, it depends, there may be multiple common factors, if it's the greatest common factor, then there is only one.  The way to do this is to list all the factors of each number.


So Factors of

18: 1,2,3,6,9,18

27: 1,3,9,27

Common Factors : 1, 3, 9

Greatest Common Factor: 9

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Sarah would like to make a 6 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of a mixture that is 80%
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Answer:  

<em>a.  The system of equations that models the situation is....</em>

<em>     0.80x+0.50y=3.60\\\\ 0.20x+0.50y=2.40</em>

<em>b.  The solution to the system:  x = 2 and y = 4 </em>

<em>The amount of 80/20 mixture is 2 pounds and the amount of 50/50              mixture is 4 pounds.</em>

Step-by-step explanation:

Suppose, the amount of 80/20 mixture is  x pounds and the amount of 50/50 mixture is  y pounds.

So, the amount of peanuts in 80/20 mixture = 0.80x pound and the amount of almonds in 80/20 mixture =0.20x pound.

And the amount of peanuts in 50/50 mixture =0.50y pound and the amount of almonds in 50/50 mixture =0.50y pound.

Now, Sarah would like to make a 6 pounds nut mixture that is 60% peanuts and 40% almonds.

So, the amount of peanuts in that mixture =(6\times 0.60)=3.60 pounds

and the amount of almonds in that mixture =(6 \times 0.40)= 2.40 pounds.

So, the system of equations will be.........

0.80x+0.50y=3.60 ...................(1)\\\\ 0.20x+0.50y=2.40...................(2)

Subtracting equation (2) from equation (1), we will get.....

(0.80x+0.50y)-(0.20x+0.50y)=3.60-2.40\\ \\ 0.60x=1.20\\ \\ x= \frac{1.20}{0.60}=2

Now, plugging this x=2 into equation (1), we will get......

0.80(2)+0.50y=3.60\\ \\ 1.60+0.50y=3.60\\ \\ 0.50y=3.60-1.60=2\\ \\ y=\frac{2}{0.50}=4

So, the amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.

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