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olya-2409 [2.1K]
3 years ago
5

Count by tens and ones to find the sum of 29+14

Mathematics
2 answers:
BabaBlast [244]3 years ago
5 0
4 tens and 3 ones , sum of 29 + 14 is 43
liberstina [14]3 years ago
4 0
The sum of 29 and 14 is 43, 4 tens and 3 ones
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The solution set for -p2 − 11p = 0 is { }. (Separate the solutions with a comma.)
ikadub [295]

Answer:

0,-11

Step-by-step explanation:

-p^2 − 11p = 0

Factor out -p

-p( p+11) =0

Using the zero product property

-p =0    p+11 =0

p =0      p = -11

3 0
3 years ago
Raquel has created a program for a robot. The robot travels 10 meters and stops. The program is designed for wheels that are 2.5
Grace [21]

Answer:

Raquel should adjust the number of rotations  to 115.81 rotations

Step-by-step explanation:

step 1

Find the circumference of the wheels that are 2.5 cm in diameter

The circumference is equal to

C=2\pi r

we have

r=2.5/2=1.25\ cm

assume

\pi =3.14

substitute

C=2(3.14) (1.25)

C=7.85\ cm

step 2

Find the number of rotations

Divide 10 meters by the circumference

10\ m=1,000\ cm

1,000/7.85=127.39\ rotations

step 3

For a diameter of 2.75 cm find how should she adjust the number of rotations so that the robot travels the same distance

Find the circumference of the wheels

The circumference is equal to

C=2\pi r

we have

r=2.75/2=1.375\ cm

assume

\pi =3.14

substitute

C=2(3.14) (1.375)

C=8.635\ cm

step 4

Find the number of rotations

Divide 10 meters by the circumference

10\ m=1,000\ cm

1,000/8.635=115.81\ rotations

3 0
3 years ago
Which linear inequality will not have a shared solution set with the graphed linear inequality? y < Five-thirdsx – 2 y < N
elena-14-01-66 [18.8K]

Answer:

the third option

Step-by-step explanation:

idk :/

8 0
3 years ago
Read 2 more answers
On a trip, a motorist drove 150 miles in the morning and 50 miles in the afternoon. His average rate in the morning was twice hi
Lina20 [59]

Answer:

Morning's average rate = 50 mph, and Afternoon's average rate = 25 mph.

Step-by-step explanation:

Suppose he drove 150 miles for X hours, then his average rate in the morning was (150/X) mph.

Given that he spent 5 hours in driving.

And he drove 50 miles for (5-X) hours, then his average rate in the afternoon was 50/(5-X) mph.

Given that his average rate in the morning was twice his average rate in the afternoon.

(150/x) = 2 * 50/(5-x)

150/x = 100/(5-x)

Cross multiplying terms, we get:-

150*(5-x) = 100*x

750 - 150x = 100x

750 = 100x + 150x

750 = 250x

x = 750/250 = 3.

It means he spent 3 hours in the morning and 2 hours in the afternoon.

So morning's average rate = 150/3 = 50 mph.

and afternoon's average rate = 50/(5-3) = 25 mph.

8 0
3 years ago
Strawberries cost $3.00 per pound. For each question
antoniya [11.8K]

A. 1/3 pound

B. 11/3 or 3.666666667

7 0
3 years ago
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