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Sonbull [250]
2 years ago
13

All parallelograms are rectangles. true or false

Mathematics
1 answer:
Marizza181 [45]2 years ago
6 0

That's false.  Not all parallelograms are rectangles, only some of them are. 
If a parallelogram wants to be a rectangle, then it has to agree to have a
right angle (90 degrees) at one corner.


(I know, I know.  Rectangles have right angles at ALL four corners. 
But if a parallelogram has one right angle AND it's still a parallelogram,
then it turns out that all four of its angles are right angles.  So if you tell
a parallelogram that one of its angles has to be a right angle, and it wants
to still be a parallelogram, then it must turn into a rectangle.)  


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Solve this system of linear equations. Separate
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Answer:

x 2 y -4

Step-by-step explanation:

13x = -54 -20y give it is A

-10x = 60 + 20y give it is B

A + B the sum of the left side of equation is equal to the sum of the right side of equation

13 + (-10x) = -54 -20y + 60 + 20y

3x = 60-54

3x = 6

x=2

so put the x value in A or B equation you can receive y value (B is easier)

y = -4

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What are the zeros of the following quadratic equation: y = 6x2 - 17x - 3
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Answer:

\displaystyle x=-\frac{1}{6}, 3

Step-by-step explanation:

Hi there!

y = 6x^2 - 17x - 3

Factor by grouping:

y = 6x^2 - 18x+1x - 3\\y = 6x(x- 3)+1x - 3\\y = 6x(x- 3)+(x - 3)\\y = (6x+1)(x- 3)

Let y=0. Apply the zero product property:

0 = (6x+1)(x- 3)

6x+1=0\\6x=-1\\\\\displaystyle x=-\frac{1}{6}

AND

x-3=0\\x=3

I hope this helps!

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If a data value in a normal distribution has a negative z-score, which of the following must be true?
mel-nik [20]
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The data value must be less than the mean.

The formula for the z value is:

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The z-value will be negative when the Numerator of the above expression will be negative. The numerator will be negative only when the Data Value is less than the mean value. For example, for a data value of 5 and mean value 8, the numerator will be -3, and when it will be divided by standard deviation, the resulting z value will be negative.

So, Third option is the correct answer. 
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