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Sonbull [250]
3 years ago
13

All parallelograms are rectangles. true or false

Mathematics
1 answer:
Marizza181 [45]3 years ago
6 0

That's false.  Not all parallelograms are rectangles, only some of them are. 
If a parallelogram wants to be a rectangle, then it has to agree to have a
right angle (90 degrees) at one corner.


(I know, I know.  Rectangles have right angles at ALL four corners. 
But if a parallelogram has one right angle AND it's still a parallelogram,
then it turns out that all four of its angles are right angles.  So if you tell
a parallelogram that one of its angles has to be a right angle, and it wants
to still be a parallelogram, then it must turn into a rectangle.)  


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The distance AB rounded to the nearest tenth = [ ? ]
docker41 [41]

Answer:

4.5 units

Step-by-step explanation:

To get the distance we need the coordinates of the points

A is ( 3,1)

B is (-1,-1)

Let A be (x1,y1) and B be (x2,y2)

So applying the formula, we have the distance as;

D = √(-1-3)^2 + (-1-1)^2

D = √(16 + 4)

D = √20

D = 4.5 units

7 0
3 years ago
Estimate what is 31.75÷8= you have to estimate tho
Afina-wow [57]
If you estimate, its around 5
5 0
3 years ago
Peter paid $79.80 for renting a tricycle for 6 hours. What was the rate per hour for renting the tricycle? (Input only numeric v
ElenaW [278]

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13.3

Step-by-step explanation:

7 0
4 years ago
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If the radius of the circle is 7 cm, find its area, rounded to 2 decimal places.
stich3 [128]

Answer:

153.94

Step-by-step explanation:

The formula for area is pi*radius^2

the radius is 7, so we do pi7^2 which is 49pi

49pi is 153.93804 which is 153.94 rounded to two decimal places

8 0
3 years ago
If QS bisects PQT, SQT=(8x- 25),PQT=(9x+34), and SQR=112, find each measure.
Goryan [66]

The values of the angles are; x = 12°, m∠PQS = 71°, m∠PQT = 142° and m∠TQR = 41°

<h3>What are the measure of the each angle?</h3>

The required angles; x, m∠PQS, m∠PQT, and m∠TQR

The given parameters are bisects ∠PQT

m∠SQT = (8·x - 25)°

m∠PQT = (9·x + 34)°

m∠SQR = 112°

We have;

m∠PQT = m∠SQT + m∠PQS (Angle addition postulate)

m∠SQT ≅ m∠PQS (Angles formed by angle bisector are congruent)

m∠SQT = m∠PQS  by Definition of congruency

m∠PQT = 2 × m∠SQT

Therefore;

(9·x + 34)° = 2 × (8·x - 25)° = (16·x - 50)°

Collecting like terms gives:

(34 + 50)° = 16·x - 9·x = 7·x

7·x = 84°

x = 84°/7 = 12°

x = 12°

m∠SQT = (8·x - 25)°

Therefore;

m∠SQT = (8 × 12 - 25)° = 71°

m∠SQT = 71°

m∠PQT = 2 × m∠SQT

∴ m∠PQT = 2 × 71° = 142°

m∠PQT = 142°

m∠PQS = m∠SQT (Angles formed by the same bisector )

∴ m∠PQS = m∠SQT = 71°

m∠PQS = 71°

m∠SQR = m∠SQT + m∠TQR (Angle addition postulate)

m∠SQT = 71°

∴  m∠SQR = 112° = 71° + m∠TQR

m∠TQR = 112° - 71° = 41°

m∠TQR = 41°

Learn more about angles here:

brainly.com/question/2882938

#SPJ1

4 0
2 years ago
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