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Eddi Din [679]
3 years ago
13

Read the following scenario:

SAT
2 answers:
mote1985 [20]3 years ago
8 0
The answer is A. Ask his friends who work at similar places
KengaRu [80]3 years ago
6 0
A. Ask his friends who work at similar places
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Two small metal cubes with masses 2. 0 g and 4. 0 g are tied together by a 5. 0-cm-long massless string and are at rest on a fri
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The energy of the system, tension in the string, and speed of each cube are respectively; U = 0.72 J, T = 14 N and (V₂, V₄) = (-22, 14)

<h3>Calculation of energy and tension in a String</h3>

We are given;

Mass of cube 1; m₁ = 2 g

Mass of cube 2; m₂ = 4 g

Distance between cubes; d = 5 cm = 0.05 m

Charges of cubes; Q = q = +2. 0 μc = 2.0 × 10⁻⁶ C

A) Formula for the energy of the system is;

U = kQq/d

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U = 0.03596/0.05

U = 0.72 J

B) Formula for the Tension is;

T = U/d

T = 0.72/0.05

T ≈ 14 N

C) Momentum is conserved, and as such the initial momentum is zero. Thus;

0 = (0.0020 × V₂) + (0.0040 × V₄)

⇒ V₂ = -2V₄

Energy is also conserved and so;

(½ × 0.0020 × (-2V₄)²) + (½ × 0.004 × (V₄)²) = 0.72 J

-0.0040V₄² + 0.002V₄² = 0.72 J

0.0060V₄² = 0.72 J

V₄² = 0.72/0.0060

V₄² = 120

V₄ = √120

V₄ ≈ 11 m/s

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Thus;

V₂ = -2(11) m/s

V₂ = -22 m/s

Thus;

(V₂, V₄) = (-22, 14)

Read more about Conservation of Momentum at; brainly.com/question/7538238

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