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snow_tiger [21]
4 years ago
13

S22 for 161+147+133+119+...

Mathematics
1 answer:
kramer4 years ago
4 0
The arithmetic sequence of 161,147,133,119
Compute the general progression formula of 161,147,133,119 d=-14, a↓n+175
Compute ᵃ₂₂ = -133
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1. What is the length of line RS?
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<h2><em>Answer</em><em>:</em></h2><h3><em>7</em><em>5</em><em>(</em><em>5</em><em>r</em><em>)</em><em>+</em><em>7</em><em>5</em><em>(</em><em>3</em><em>d</em><em>)</em><em>+</em><em>7</em><em>5</em><em>(</em><em>4</em><em>f</em><em>)</em></h3>

<em>Solution</em><em>,</em>

<em>Cost </em><em>of </em><em>roses </em><em>in </em><em>1</em><em> </em><em>bouquet=</em><em>5</em><em>r</em>

<em>Cost </em><em>of </em><em>daisies </em><em>in </em><em>1</em><em> </em><em>bouquet=</em><em>3</em><em>d</em>

<em>cost </em><em>of </em><em>green </em><em>filler </em><em>in </em><em>1</em><em> </em><em>bouquet</em><em>=</em><em>4</em><em>f</em>

<em>Total </em><em>no.</em><em> </em><em>of </em><em>bo</em><em>u</em><em>q</em><em>u</em><em>e</em><em>t=</em><em>7</em><em>5</em>

<em>cost </em><em>of </em><em>one </em><em>bouquet=</em><em>5</em><em>r</em><em>+</em><em>3</em><em>d</em><em>+</em><em>4</em><em>f</em>

<em>total=</em><em>7</em><em>5</em><em>(</em><em>5</em><em>r</em><em>+</em><em>3</em><em>d</em><em>+</em><em>4</em><em>f</em><em>)</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>7</em><em>5</em><em>(</em><em>5</em><em>r</em><em>)</em><em>+</em><em>7</em><em>5</em><em>(</em><em>3</em><em>d</em><em>)</em><em>+</em><em>7</em><em>5</em><em>(</em><em>4</em><em>f</em><em>)</em>

<em>hope </em><em>it</em><em> helps</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

8 0
3 years ago
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