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almond37 [142]
3 years ago
8

You plan to charge $10 per shirt for the first 50 shirts. If you order more than $50 shirts you plan to sell each shirt for $8 e

ach. How much would you charge a customer for purchasing 125 shirts?
Mathematics
1 answer:
Juliette [100K]3 years ago
7 0

Answer:

You would charge 1,100 dollars.

Step-by-step explanation:

Since the first fifty shirts are 10 bucks each, you would subtract that 50 from 125, which gives you 75. Now with that 50,you would multiply it by 10, which is 500. Now put that 500 to the side, and do your remaining 75 times the 8 dollars that is now being charged. You should get 600. Finally, you add the 500 that you put aside and the 600 to get 1100.

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Answer:

A = 43°

b = 25.8 (3 sig. fig.)

c = 14.5 (3 sig. fig.)

Step-by-step explanation:

Using angle sum of triangle, we get A = 180 - 104 - 33 = 43°

Using sin law,

b/sin104 = 18.1/sin43

b = 25.8 (3 sig. fig.)

c/sin33 = 18.1/sin43

c = 14.5 (3 sig. fig.)

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Step-by-step explanation:

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A poll conducted in 2013 found that 55% of U.S. adult Twitter users get at least some news on Twitter (Pew, 2013). The standard
alina1380 [7]

Answer:

The 99% confidence interval for the fraction of U.S. adult Twitter users who get some news on Twitter is between 49.34% and 60.66%, which means that we are 99% sure that the true percentage of US adult Twitter users who get some news is in this interval.

Step-by-step explanation:

Confidence interval:

A confidence interval has the following format:

M \pm zs

In which M is the sample mean, z is related to the confidence level and s is the standard error.

55% of U.S. adult Twitter users get at least some news on Twitter (Pew, 2013). The standard error for this estimate was 2.2%.

This means that M = 55, s = 2.2

99% confidence level

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Upper bound:

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The 99% confidence interval for the fraction of U.S. adult Twitter users who get some news on Twitter is between 49.34% and 60.66%, which means that we are 99% sure that the true percentage of US adult Twitter users who get some news is in this interval.

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