Answer:
Number of fish in 2006 = 845 fishes (Approx.)
Step-by-step explanation:
Given;
Number of fish in 2000 = 1,150 fishes
Decreasing rate = 5% per year
Find:
Number of fish in 2006
Computation:
Exponential decay function:
F = P[1-r]ⁿ
Number of year = 2006 - 2000
Number of year = 6 year
Number of fish in 2006 = 1,150[1-5%]⁶
Number of fish in 2006 = 1,150[1-0.05]⁶
Number of fish in 2006 = 1,150[0.95]⁶
Number of fish in 2006 = 1,150[0.735]
Number of fish in 2006 = 845.25
Number of fish in 2006 = 845 fishes (Approx.)
Answer:b
Step-by-step explanation:
Answer:
64 and 81
Step-by-step explanation:
Answer sorry i cant help u rn
Step-by-step explanation:
Answer:
if no discount is allowed
MP = SP = 1500
sp with vat = sp = vat amount
vat amount = vat% of sp
= 10% 0f 1500
= 150
sp with vat = sp = vat amount
= 1500 + 150
= 1650
