Answer:
The answer is
<h3>81x⁴ + 216x³ + 216x² + 94x + 16</h3>
Step-by-step explanation:
(3x + 2)⁴
<u>Using the Pascal's triangle</u>
For an exponent of 4 we have
( a + b)⁴ = a⁴ + 4a³b + 6a²b² + 4ab³ + b³
Using a = 3x and b = 2 we have
( 3x +2)⁴ = ( 3x)⁴ + 4 [ (3x)³(2) ] + 6[ (3x)²(2)²] + 4 [ 3x(2)³ ] + 2⁴
Expand and simplify
That's
➢ ( 3x +2)⁴ = 81x⁴ + 4[ (27x³)(2) ] + 6 [ (9x²)(4) ] + 4 [ 3x(8) ] + 16
➢ 81x⁴ 4( 54x³) + 6(36x²) + 4( 24x) + 16
We have the final answer as
<h3>81x⁴ + 216x³ + 216x² + 94x + 16</h3>
Hope this helps you
Answer:
<h3> <u>Y</u><u>E</u><u>S</u><u> </u></h3>
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Proportional Relationships
A proportional relationship is one in which two quantities vary directly with each other. We say the variable y varies directly as x if:
y=kx
for some constant k , called the constant of proportionality .
(Some textbooks describe a proportional relationship by saying that " y varies proportionally with x " or that " y is directly proportional to x .")
This means that as x increases, y increases and as x decreases, y decreases-and that the ratio between them always stays the same.
The graph of the proportional relationship equation is a straight line through the origin.
Step-by-step explanation:
First of all we need to know the formula for the circumference which is: 
We don't have the radius. What we only have is the area; therefore, we must use the area formula and extract the radius from it.
The formula for the area is: 
Solve for r;
![r^2=\frac{A}{\pi}\\ r=\sqrt[]{\frac{A}{\pi} }](https://tex.z-dn.net/?f=r%5E2%3D%5Cfrac%7BA%7D%7B%5Cpi%7D%5C%5C%20r%3D%5Csqrt%5B%5D%7B%5Cfrac%7BA%7D%7B%5Cpi%7D%20%7D)
![r=\sqrt[]{\frac{50.24inch^2}{3.14} }](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B%5D%7B%5Cfrac%7B50.24inch%5E2%7D%7B3.14%7D%20%7D)
![r=\sqrt[]{16inch^2}\\ r=4inch](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B%5D%7B16inch%5E2%7D%5C%5C%20r%3D4inch)
Now that we've found the radius, we simply plug it into the circumference formula.
Answer:
this may help you.look it once.
10k^4+10k^3+8k^2+8k+10/k+1 not sure if this is what you are looking for or not hope it helps
