<u>Area of circle:</u>
C
=πr²
=π(d/2)²
=3.14×(20/2)²
=3.14×100
=314 m²
<u>Area of right angled triangle:</u>
T
=(base × perpendicular)/2
=(56×56)/2
=1568 m²
<u>Area of shaded region:</u>
=T-C
=1568-314
=1254 m² >>>>Answer
Answer:
Either a= -7 or a= 0
Step-by-step explanation:
Pull out like factors:
a2 + 7a = a • (a + 7)
a • (a + 7) = 0
A) The equation for circumference is C=2piR. So Filling in for circle A we have 28.26=2*pi*4.5 so we want to isolate pi which I'm gonna call x for it's easier for me xD. So we're gonna start by dividing 4.5 from each side which is gonna leave us with 6.28=2*x which gives you x(pi)= 3.14. For circle B we have 15.70=2*x*2.5 isolate x by first dividing 2.5 which leaves us again with 6.28=2x and x= 3.14.
B) The equation for area is A=piR^2. So again for circle A we have 63.585=x9^2. This one is harder but also are you sure that the area is 63.585 it's supposed to be 254.469 (We'll come back to this)
C) The observation you can make about the value of pi for circles A and B is that it stays consistent at 3.14
Answer:
Step-by-step explanation:
We would use the t- distribution.
From the information given,
Mean, μ = 2950
Standard deviation, σ = 115
number of sample, n = 25
Degree of freedom, (df) = 25 - 1 = 24
Alpha level,α = (1 - confidence level)/2
α = (1 - 0.98)/2 = 0.01
We will look at the t distribution table for values corresponding to (df) = 24 and α = 0.01
The corresponding z score is 2.492
We will apply the formula
Confidence interval
= mean ± z ×standard deviation/√n
It becomes
2950 ± 2.492 × 115/√25
= 2950 ± 2.492 × 23
= 2950 ± 57.316
The lower end of the confidence interval is 2950 - 57.316 =2892.68
The upper end of the confidence interval is 2950 + 57.316 = 3007.32
The solution is correct.
Answer:
180 -angle BCD
Step-by-step explanation:
if you've found angle BCD you should be able to find angle DCE as angles on a straight line equal 180°
